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How many liters are within 3.5 mol of helium gas at STP?
1 mole = 22.414 liters So, 3.5 mole = 78.45 liters
How can you calculate the number of liters of 2.30 mole of helium gas at STP?
1 mole (or 4 g of He) occupies 22.414 liters. So, 2.3 mole occupies 2.3 x 22.414 liters = 51.5522 liters
What does avogadros law say about a gas at STP?
1 mole of gas at STP occupies 22.4 liters.
Under what sets of condition will a 0.50 mole sample of helium occupy a volume of 11.2 liters?
A 0.50 mole sample of helium will occupy a volume of 11.2 liters under standard temperature and pressure (STP) conditions, which are 0 degrees Celsius (273.15 K) and 1 atmosphere pressure. At STP, one mole of any gas occupies a volume of 22.4 liters.
Under what sets of conditions will a 0.50 mole sample of helium occupy a volume of 11.2 liters?
At STP, 1 mole of a gas will occupy 22.4 liters; or 0.5 mole will occupy 11.2 liters.
At stp how many moles of helium would occupy 1.00l?
At standard temperature and pressure, 1 mole of any gas will occupy 22.4 liters. Set up a direct proportion of 22.4 liters/1 mole = 1 liter/x moles and solve for x. You get 0.045 moles.
How many liters are in 1.84 moles of helium?
1 mole occupies 22.414 liters So, 1.84 moles will occupy 41.242 liters
How many moles of ammonia gas NH3 are required to fill a volume of 50 liters at STP?
At standard temperature and pressure (STP), one mole of any ideal gas occupies 22.4 liters. To find the number of moles of ammonia gas (NH₃) required to fill a volume of 50 liters, you can use the formula: moles = volume (liters) / volume per mole (liters/mole). Therefore, the calculation is 50 liters / 22.4 liters/mole = approximately 2.24 moles of NH₃ are needed.
What is the volume of one mole of any gas at STP?
At STP, 1 mol or 6.02x10^23 representative particles, of any gas occupies a volume of 22.4 Liters. (chemistry)
Calculate the gram atom in 22.4 liters of helium?
To calculate the number of gram atoms in 22.4 liters of helium, we first need to convert the volume to moles using the ideal gas law. Since helium is a monoatomic gas, 1 mole of helium is equivalent to 4 grams (its molar mass). Therefore, the number of gram atoms in 22.4 liters of helium would be 22.4 liters * (1 mole / 22.4 liters) * (4 grams / 1 mole) = 4 grams.
How do you calculate the number of liters of 3.30 moles of helium at stp?
1 mole occupies 22.414 liters So, 3.30 moles will occupy 73.966 liters.
What volume does 0.50 mole of NH3 at STP occupy?
1 mole occupies 22.4 liters. 0.5 moles occupies 11.2 liters at STP.
