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What is the ratio volume of volume occupied by 1 mole of o2 and 1 mole of o3?
At standard temperature and pressure (STP), 1 mole of any ideal gas occupies approximately 22.4 liters. Therefore, 1 mole of O₂ occupies 22.4 liters, and 1 mole of O₃ also occupies 22.4 liters, as it is also a gas under these conditions. Thus, the volume ratio of 1 mole of O₂ to 1 mole of O₃ is 1:1.
How many liters are within 3.5 mol of helium gas at STP?
1 mole = 22.414 liters So, 3.5 mole = 78.45 liters
How can you calculate the number of liters of 2.30 mole of helium gas at STP?
1 mole (or 4 g of He) occupies 22.414 liters. So, 2.3 mole occupies 2.3 x 22.414 liters = 51.5522 liters
What does avogadros law say about a gas at STP?
1 mole of gas at STP occupies 22.4 liters.
Under what sets of condition will a 0.50 mole sample of helium occupy a volume of 11.2 liters?
A 0.50 mole sample of helium will occupy a volume of 11.2 liters under standard temperature and pressure (STP) conditions, which are 0 degrees Celsius (273.15 K) and 1 atmosphere pressure. At STP, one mole of any gas occupies a volume of 22.4 liters.
Under what sets of conditions will a 0.50 mole sample of helium occupy a volume of 11.2 liters?
At STP, 1 mole of a gas will occupy 22.4 liters; or 0.5 mole will occupy 11.2 liters.
How many liters of He gas would 1 mol of He occupy at STP?
At standard temperature and pressure (STP), 1 mole of any ideal gas occupies 22.4 liters. Therefore, 1 mole of helium (He) gas would occupy 22.4 liters at STP.
At stp how many moles of helium would occupy 1.00l?
At standard temperature and pressure, 1 mole of any gas will occupy 22.4 liters. Set up a direct proportion of 22.4 liters/1 mole = 1 liter/x moles and solve for x. You get 0.045 moles.
How many liters are in 1.84 moles of helium?
1 mole occupies 22.414 liters So, 1.84 moles will occupy 41.242 liters
What is the number of liters of 1 mole of CO2(9)?
At standard temperature and pressure (STP), 1 mole of any ideal gas occupies approximately 22.4 liters. Therefore, 1 mole of CO2 (carbon dioxide) would also occupy about 22.4 liters under these conditions. However, if the temperature and pressure differ from STP, the volume may vary accordingly.
How many moles of ammonia gas NH3 are required to fill a volume of 50 liters at STP?
At standard temperature and pressure (STP), one mole of any ideal gas occupies 22.4 liters. To find the number of moles of ammonia gas (NH₃) required to fill a volume of 50 liters, you can use the formula: moles = volume (liters) / volume per mole (liters/mole). Therefore, the calculation is 50 liters / 22.4 liters/mole = approximately 2.24 moles of NH₃ are needed.
What is the volume of one mole of any gas at STP?
At STP, 1 mol or 6.02x10^23 representative particles, of any gas occupies a volume of 22.4 Liters. (chemistry)
