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Subnets are created in powers of 2 due to the way netmasks work.

To accomodate 10 addresses, you would need a /28 (255.255.255.240) netmask, which would provide 14 usable IP addresses. Here are the details of that mask in a private network address area (192.168.x.x)

Output from the unix "ipcalc" program:

Address: 192.168.1.0 11000000.10101000.00000001.0000 0000

Netmask: 255.255.255.240 = 28 11111111.11111111.11111111.1111 0000

Wildcard: 0.0.0.15 00000000.00000000.00000000.0000 1111

=>

Network: 192.168.1.0/28 11000000.10101000.00000001.0000 0000

HostMin: 192.168.1.1 11000000.10101000.00000001.0000 0001

HostMax: 192.168.1.14 11000000.10101000.00000001.0000 1110

Broadcast: 192.168.1.15 11000000.10101000.00000001.0000 1111

Hosts/Net: 14 Class C, Private internet

With the /28 netmask, 192.168.1.0 is the network address, and unusable. 192.168.1.15 is the broadcast address, and is also non-assignable. This gives 14 usable addresses. A /29 netmask (one bit less) gives 6 usable addresses.

To create 10 subnets, the size of the subnets would need to be known, and the process is similar, but the subnets would have different start and end addresses.

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12y ago

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