20 to 30kg
for residential building 1 sqm steel required =8kgs
when you need to find mass or weight of 80mm thick mild steel plate then just measure it's length and width and multiply by it's mass or weight per sqm. volume of steel = 2.5x1.25x.08 = 0.25 cub.m assuming your steel to be mild steel (if the steel is different then place appropriate density for it and you need to workout as below) density of mild steel= 7850 kg/m3 mass of steel = 0.25x7850 = 1962.50 Kg weight of steel = 1962.50x9.81 = 19252.13 N A little time saver for next time: Area of steel = 2.5x1.25 = 3.125 sqm so mass per sqm = 1962.50/3.125 = 628 Kg weight per sqm = 19252.13/3.125 = 6160.68 N
144 sqft is 13.378 sqm
The area is 110637.523 sqm.
The size of each of the squares is required.
400 sqm
60 square metres!
formula of steel weight per sqm
Multiply them
There are various factors that we need to consider while setting up a solar power plant. A solar company can give you accurate estimation of land and all other things required to set up 1 MW solar power plant.So let's do some calculations on the area required for 1 MW solar panels only:1MW = 1000kW = 1000000WIF 250 W solar panels are used -THEN no of solar panels = 1000000W/250 =4000 panels1 250 W solar panel requires 1.6 SqM of land area,So1.6 SqM * 4000 = 6400 SqMThis is the area required for solar panels. Again you'll have to to add extra space to avoid shadowing on solar panels.So technology wise, the land required for a 1 MW power plant setup is around 4.5-5 acres for Crystalline technology and around 6.5-7.5 acres for Thin-Film technologyNow coming back to you question - 1 60kW solar inverter requires around 1.08 SqM area. So,1000kW/60kW = 17 Inverters17 X 1.08 SqM = 18.38 SqMSo around 20 SqM space is required for 1 MW solar inverter.
in rizal - 6000/sqm. ncr - 10000/sqm.
Cubic metres is a measure of volume. Square metres is a measure of area. The two cannot be converted.