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What are the memory addresses from 0 to 640kb known as?
The memory addresses from 0 to 640 KB are known as conventional memory. This range was primarily used in early personal computers, specifically in the context of the x86 architecture. It was the area of RAM available for use by MS-DOS and older operating systems, where most applications and programs would operate. Beyond this range, from 640 KB to 1 MB, is known as upper memory.
Why is the conventional has logical memory allocation of 0 to 640 KB?
The original 1981 IBM PC used an Intel 8088 CPU which had an address space of 1 megabyte. The lower 640KB of the address space (a huge amount for the day) was dedicated to RAM and the rest was dedicated to ROM and graphics memory. The ROM contained BIOS for booting and simple device drivers, and a BASIC interpreter. Intel x86 CPUs from the 286 onward have had much larger address spaces, but for backward compatibility they all have hardware modes where they can pretend to be an 8086, with its 1MB limitation.
How many address lines can access a 16MB memory?
for 16 MB memory has 24 address lines
What is the memory address of the last byte of a 1GB memory?
In a 1GB memory space, the total number of bytes is (1 \times 2^{30} = 1,073,741,824) bytes. Since memory addresses typically start at 0, the memory address of the last byte would be (1,073,741,824 - 1 = 1,073,741,823). Therefore, the memory address of the last byte of a 1GB memory is 1,073,741,823.
What are array of string pointers?
An array of pointers to string would contain, per array position, a number dictating which memory address holds the string data. For example, position [0] in an array would contain a memory address. This memory address can be de-referenced to obtain the actual information held within that memory address.
What is the first test Test 0 performed by memtest86?
Test 0 [Address test, walking ones, no cache]Tests all address bits in all memory banks by using a walking ones address pattern.
What is offset address?
An offset address is a relative address rather than an absolute address. You use offsets to refer to memory relative to an absolute address. For instance, array indices are implemented using offsets from the start address of the array, such that element 0 is at offset 0 and element 5 is at offset 5.
How many bit address bus you need to address the memory locations from 0 to 2059 of a RAM?
To address memory locations from 0 to 2059, you need to determine how many unique addresses are required. The total number of addresses is 2059 - 0 + 1 = 2060. To find the number of bits needed for the address bus, calculate (2^n \geq 2060). Since (2^{11} = 2048) (not sufficient) and (2^{12} = 4096) (sufficient), you need a 12-bit address bus.
What would be the hexadecimal representation of the largest memory address in a memory consisting of 4MB if each cell had a one-byte capacity?
If the architecture allows each individual byte to be adressed then there are 4,000,000 possible addresses ranging from 0 to 3,999,999. So the largest address is 3,999,999 which is 3D08FF in hexadecimal representation
How many NOT gates are needed to turn on a memory IC if the address 10000001 is at the CE input of the chip?
To turn on a memory IC with an active-low Chip Enable (CE) input, you need to ensure that the CE signal is low (0) when the address 10000001 is provided. If the address corresponds to a high signal (1), one NOT gate is needed to invert the address signal to a low signal (0) for the CE input. Therefore, only one NOT gate is required to achieve this.
What Debug command dumps data at the beginning of the memory address space?
In my debugger it is%D V'0'your debugger may use other commands.
What is defference between direct and indirect address?
The I bit is 0 so the instruction is recognice as a direct address instruction The indirect address instruction needs 2 referance to memory to fetch & opened The I bit is 1 so the instruction is recognice as a indirect address instructionhe
