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Why does memory access take more machine cycle than register access?
Because of different in speeds of cpu the system bus and the memory circut
Why register to register instruction is faster?
Register to register addressing mode is faster because you don't have to do an extra memory access cycle or more.Register to register addressing mode is faster because:Registers are part of and are directly accessibility by the CPU assembly.They electronics that make up a register use more expensive but faster circuitry.Since it does not require memory access, the steps and time involved in memory address decoding and memory access are skipped.
Why is it necessary to access register instead of memory?
i need the answer. please
How many machine cycles do ADD and LHLD instructions have?
In the context of the 8085 microprocessor, the ADD instruction takes 1 machine cycle to execute, as it operates directly on the accumulator and the specified register. On the other hand, the LHLD (Load H and L Direct) instruction requires 3 machine cycles, as it involves reading data from a specified memory address into the L and H registers.
How many machine cycle are required in LDA 2050H?
It will require 4 machine cycles, 1.opcode fetch 2.memory read 3. memory read 4. memory write
Why does it take 5 machine cycles in the SHLD instruction of 8085 microprocessor?
fetch SHLD opcode bytefetch direct address least significant bytefetch direct address most significant bytewrite L register contents byte to memorywrite H register contents byte to memory
Draw and explain the bloack Daigram of Von Neumann machine?
Block diagram of the von Neumann architecture: MQ, multiplier quotient register; IR, instruction register; IBR, instruction buffer register; MAR, memory address register; MDR, memory data register
How many machine cycles requires to complete the execute IN 84H in 8085?
The instruction IN 84H in the 8085 microprocessor requires 5 machine cycles to complete. This includes 1 opcode fetch cycle and 4 memory read cycles. The opcode fetch retrieves the instruction from memory, while the read cycles are used to read the data from the specified input port.
Timming diagram for lda instruction in microprocessor 8085?
The timing diagram for the LDA (Load Accumulator Direct) instruction in the 8085 microprocessor involves several key phases. Initially, the opcode is fetched from memory, which takes 4 clock cycles. Next, the address of the data to be loaded into the accumulator is specified in the next two cycles, followed by another two cycles to read the data from the specified memory location into the accumulator. The entire process typically takes 7 machine cycles, including the necessary memory access time.
What is a memory mapped register?
A memory mapped register is a register that has its specific address stored in a known memory location.
IS OPCODE FETCH MACHINE CYCLE ENOUGH FOR THE INTRUCTION MOV MA IN 8085 TIMING DIAGRAM?
In the 8085 microprocessor, the opcode fetch machine cycle is not sufficient on its own for executing the MOV MA instruction. While the opcode fetch cycle is responsible for retrieving the instruction from memory, additional machine cycles are required to perform the data transfer or execution of the instruction. Specifically, the MOV MA instruction involves both an opcode fetch cycle and a memory access cycle to complete the operation. Therefore, multiple machine cycles are necessary for executing this instruction effectively.
How many machine cycle are neede to execute STA 1800?
The STA (Store Accumulator) instruction typically requires one machine cycle to execute, as it directly stores the value from the accumulator into the specified memory address. However, the total number of cycles may vary depending on the specific architecture and its memory access timing. In many systems, it could take one cycle for the instruction fetch and another for the memory write, totaling two cycles. Always refer to the specific architecture documentation for precise details.
