The molar mass of NaNO3 is 85.0 g/mol. Therefore, 1 mole of NaNO3 is equal to 85.0 grams.
Learn spelling first, then come back... KCl Degrees Celcius
The amount of solute that will dissolve in water at a specific temperature depends on the solubility of the solute at that temperature. You need to check the solubility of the specific solute at the specified temperature (in degrees Celsius) to determine how many grams will dissolve in 100 grams of water.
100 g water dissolve 45,8 g potassium chloride at 50 o 0C.
For this you need the atomic (molecular) mass of NaNO3. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. NaNO3=85.0 grams60.1 grams NaNO3 / (85.0 grams) = .707 moles NaNO3
At 10 degrees Celsius, potassium chloride (KCl) has a solubility of approximately 30 grams per 100 grams of water. To dissolve 350 grams of KCl, you would need about 1,166.67 grams of water, calculated by taking the ratio of the solubility: ( 350 , \text{g KCl} \times \frac{100 , \text{g water}}{30 , \text{g KCl}} ). Thus, around 1,167 grams of water are required to fully dissolve 350 grams of KCl at that temperature.
To calculate the amount of NaNO3 needed to form a saturated solution at 45°C, the solubility of NaNO3 at this temperature must be known. Once this value is determined, the grams of NaNO3 required can be calculated using the solubility value and the saturation point equation.
Solubility of NaNO3 is 1.25 kg/kgwater. There are solubility vs temperature curve of many sodium salt available in the internet and text book.
67.0 grams of caffeine will dissolve in 100 mL of water at 100 degrees Celsius. 100mL of water = 100g of water so.. 67.0 grams of water will dissolve in 100 grams of water at 100 degrees Celsius. I pretty sure this is right, I was searching for the answer myself and it seems to work. But more accurately you will need to find the density of water at 100 ºC which is 0.9584 g/mL. So, 100g/0.9584 g/mL equals about 104 mL. Then 104 mL x 67.0g/100 mL = 69.9 g.
You need to find a graph of solubility in your textbook. It should have temperature on the x-axis and "grams dissolved per 100 grams H2O" on the y-axis (or some such.) Sodium nitrate is less soluble in cool water than warm. Use the graph to determine how many grams are dissolved at 50°C, multiplying by 2 since there are 200 grams H2O. Then determine how many grams are dissolved at 20°C, again multiplying by 2. Subtract the two numbers to find the grams that will precipitate
Instead of waiting for the answer, I ended up solving it. lol 300grams of H20 X 110grams of KNO3/100 grams of H20 = 330 grams of KNO3 The grams of H20 both cancel out and leave you with 330 grams of KNO3 Containing the solubility of KNO3. At 60 degrees celsius the KNO3 grams were 110, which is (over) / 100grams of H20. Hope this helps with this workbook problem :)
Approximately 42 grams of KCl can dissolve in 100 grams of water at 80°C.