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Using this as a reference: http://www.energyexcess.com/node/216
2 kg of water takes 1700 kJ of gas (yes its only 40% efficient) to reach boiling in 8 minutes.
Heat rate = 1700 / (8*60) kJ/s = 3.5 kJ/s (also known as kW)
Now calorific value of LPG = 46 kJ/g
Therefore you have about 0.077 g/s of LPG consumption.
Of course the reference doesn't mention the burner geometry - so the flow rate will vary - but you do get a ball park figure.
As a more crude way - we have 14.2 kg LPG cylinders in India.
One cylinder lasts about 5 months. About 1/2 hour to 1 hour cooking time per day.
Makes it total 75 to 150 hours. Lets take 100 hours as a rough figure.
14.2 kg is vented out in 100 hours.
That means 14200 g in 360000 s
= 0.04 g/s
Almost half of what has been calculated above.
So the reference (first line) definitely uses extra large sized burners (commercial).
What else can I help you with?
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.5 gpm
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