number of moles = mass/molar mass n= m/Mr n=512/ (12.01*6)+(1.008x12)+(16x6) n= 512/180.156 n= 2.842 (rounded to three decimal places, otherwise; 2.841981394)
To determine the number of atoms in 5.72 grams of glucose, you first need to calculate the number of moles of glucose using its molar mass. Then, you can use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles to atoms. Given that the molar mass of glucose is approximately 180.16 g/mol, you can then calculate the number of atoms in 5.72 grams of glucose.
To determine the number of molecules in 720 grams of C6H12O6 (glucose), you first need to calculate the number of moles present. The molar mass of glucose is 180.16 g/mol. Dividing 720 grams by the molar mass gives you 4 moles of C6H12O6. One mole of any substance contains Avogadro's number of molecules, which is approximately 6.022 x 10^23. Therefore, 4 moles of C6H12O6 would contain about 2.409 x 10^24 molecules.
0.260 mole C6H12O6 (6.022 X 10^23/1 mole C6H12O6) = 1.57 X 10^23 atoms of glucose
They are different compounds with different molecules:- the chemical formula of glucose is C6H12O6- the chemical formula of sucrose is C12H22O11
To determine the number of carbon atoms in 7.11g of glucose, you first need to calculate the moles of glucose using its molar mass. The molar mass of glucose (C6H12O6) is 180.16 g/mol. Next, calculate the number of moles of carbon in one mole of glucose (6 moles). Finally, multiply the moles of glucose by the number of moles of carbon to find the total number of carbon atoms in 7.11g of glucose.
To find the number of molecules present in 936 g of glucose, you would first calculate the number of moles of glucose using its molecular weight. Then, you would use Avogadro's number (6.022 x 10^23 molecules/mol) to convert moles to molecules.
To find the number of atoms in 18 grams of glucose, we first need to calculate the number of moles of glucose using its molar mass. The molar mass of glucose is approximately 180 grams/mol. Therefore, 18 grams of glucose is equal to 0.1 moles. Since 1 mole of glucose contains 6.022 x 10^23 atoms (Avogadro's number), 0.1 moles of glucose would contain 6.022 x 10^22 atoms.
What is the smallest number of glucose molecules that can form a polysaccharide?
To find the mass of 1.64x10^23 molecules of C6H12O6, you need to determine the molar mass of one molecule of C6H12O6. Then, use Avogadro's number (6.022x10^23 molecules/mol) to convert the number of molecules to moles. Finally, multiply the number of moles by the molar mass to get the mass in grams.
Molarity = moles of solute/Liters of solution Find moles glucose, which is molecular formula------C6H12O6 154 grams C6H12O6 (1 mole C6H12O6/180.156 grams) = 0.8548 moles C6H12O6 Molarity = 0.8548 moles C6H12O6/1 Liter = 0.855 M glucose ---------------------------
The Problem: __CO2 + __H2O --> C6H12O6 + 6O2 You need to balance the equation to solve the blanks above, which means making sure that there are the same number of C's, H's, and O's on each side of the arrow. The answer is 6 molecules of glucose and 6 molecules of water.
C48 H96 O48 (C6H12O6 x 8) ~ new edit : actually the answer is C48 H82 O41 this is because after you combine every two monomers (then to polymers) you must remove water (H2O) this is by dehydration synthesis it says that you need to remove water to make a bond so the final answer is C48 H82 O41 :D