22 grams carbon dioxide (0.5 moles)
To find the grams of carbon dioxide produced, start by calculating the moles of each reactant using their molar masses. Then determine the limiting reactant (the one that forms less product). In this case, oxygen is the limiting reactant. Use the mole ratio from the balanced chemical equation to find the moles of carbon dioxide produced. Finally, convert moles of carbon dioxide to grams using its molar mass.
If 15 liters of propane are completely consumed 90,25 grams of carbon dioxide are produced.
If ethylene (C2H4) undergoes complete combustion, it will react with oxygen to produce carbon dioxide and water. The balanced chemical equation for the combustion of ethylene is: C2H4 + 3 O2 → 2 CO2 + 2 H2O. Since 1 mol of C2H4 produces 2 mol of CO2, the molar ratio is 1:2. Therefore, starting with 45 grams of ethylene, it will result in 120 grams of carbon dioxide being produced.
Balanced equation. C + O2 -> CO2 22.2 grams carbon (1 mole C/12.01 grams)(1 mole CO2/1 mole C) = 1.85 moles carbon dioxide produced -------------------------------------------------
The molar mass of carbon dioxide is 44.01 g/mol (12.01 g/mol for carbon + 2 * 16.00 g/mol for oxygen). To find the number of moles in 418 grams, divide 418 grams by the molar mass of carbon dioxide. The calculation is 418 g / 44.01 g/mol = 9.50 moles of carbon dioxide.
11 grams because all is reacted and there is no reactant left over, although if there were only 3 grams of carbon there would have to be 6 grams of oxygen for this to be viable as carbon dioxide is CO2 so the question asked was itself wrong.
To find the grams of carbon dioxide produced, start by calculating the moles of each reactant using their molar masses. Then determine the limiting reactant (the one that forms less product). In this case, oxygen is the limiting reactant. Use the mole ratio from the balanced chemical equation to find the moles of carbon dioxide produced. Finally, convert moles of carbon dioxide to grams using its molar mass.
22 grams of carbon dioxide contains 12 grams of carbon. This amount of carbon can combine with 32 grams of oxygen to form 44 grams of carbon dioxide.
If 15 liters of propane are completely consumed 90,25 grams of carbon dioxide are produced.
Balanced equation always and first. Decomposition reaction. CO2 -> C + O2 440 grams CO2 (1 mole CO2/44.01 grams)(1 mole O2/1 mole CO2)(32 grams/1 mole O2) = 319.93 grams O2 ( call it 320 grams )
The equation for the reaction is C + O2 -> CO2. The relevant gram atomic masses are 12.011 for carbon and 15.9994 for oxygen. Therefore, the ratio of the mass of carbon dioxide produced to carbon burnt is [2(15.9994) + 12.011]/12.011 or about 3.66. From burning 3 grams of carbon, the mass of carbon dioxide produced is therefore 1 X 101 grams, to the justified number of significant digits.
First, calculate the moles of propanol (C3H7OH) using its molar mass. Then, use the balanced chemical equation for the combustion reaction of propanol to find the moles of carbon dioxide produced. Finally, convert moles of carbon dioxide to grams using its molar mass to find the mass produced.
We need 14,8 g oxygen.
If ethylene (C2H4) undergoes complete combustion, it will react with oxygen to produce carbon dioxide and water. The balanced chemical equation for the combustion of ethylene is: C2H4 + 3 O2 → 2 CO2 + 2 H2O. Since 1 mol of C2H4 produces 2 mol of CO2, the molar ratio is 1:2. Therefore, starting with 45 grams of ethylene, it will result in 120 grams of carbon dioxide being produced.
Look up the molecular weight of carbon dioxide in the periodic table. The formula for carbon dioxide is CO2, which means one atom of carbon and two atoms or oxygen per molecule of carbon dioxide. Carbon has molecular weight of 12. Oxygen molecular weight is 16. Total 12+16+16= 44 11 grams/44 grams/mole=0.25 moles of carbon The grams of water and combustion of 7.5 grams are totally irrelevant. They are only given to possibly confuse you.
Weight:1.45 grams volume: 6.789
To find the grams of carbon dioxide produced, first determine the moles of 1-heptanol using its molar mass. Then, use the balanced combustion equation of 1-heptanol to find the moles of CO2 produced. Finally, convert moles of CO2 to grams using its molar mass.