N = n x 6.02X1023
N = 0.100 mol x 6.02 x 1023
N = 6.02 X 1022
There are approximately 2.65 × 10^26 bromine molecules in the flask. This is calculated by multiplying Avogadro's number (6.022 × 10^23 molecules/mol) by the number of moles of bromine present in the flask (440 mol).
To determine the number of bromine molecules, you need to first convert the mass of liquid bromine to moles using its molar mass. Then, use Avogadro's number (6.022 x 10^23) to convert moles to molecules.
The number of bromine molecules present in the flask can be calculated using Avogadro's number, which is 6.022 x 10^23 molecules/mol. In this case, there are 0.380 mol of bromine, so the number of bromine molecules present is 0.380 mol x 6.022 x 10^23 molecules/mol.
One mole of any substance contains approximately 6.022 x 10^23 particles (Avogadro's number). Therefore, 0.290 mol of liquid bromine contains 0.290 mol x 6.022 x 10^23 molecules/mol ≈ 1.74 x 10^23 bromine molecules.
The chemical formula for bromine when it is a liquid is Br2, indicating that it consists of diatomic molecules.
There are approximately 2.65 × 10^26 bromine molecules in the flask. This is calculated by multiplying Avogadro's number (6.022 × 10^23 molecules/mol) by the number of moles of bromine present in the flask (440 mol).
To determine the number of bromine molecules, you need to first convert the mass of liquid bromine to moles using its molar mass. Then, use Avogadro's number (6.022 x 10^23) to convert moles to molecules.
Liquid bromine is a monoatomic molecule as it is a liquid
The number of bromine molecules present in the flask can be calculated using Avogadro's number, which is 6.022 x 10^23 molecules/mol. In this case, there are 0.380 mol of bromine, so the number of bromine molecules present is 0.380 mol x 6.022 x 10^23 molecules/mol.
One mole of any substance contains approximately 6.022 x 10^23 particles (Avogadro's number). Therefore, 0.290 mol of liquid bromine contains 0.290 mol x 6.022 x 10^23 molecules/mol ≈ 1.74 x 10^23 bromine molecules.
The chemical formula for bromine when it is a liquid is Br2, indicating that it consists of diatomic molecules.
.310 MOLES 6.022*(10^23 ) molecules --------------- times ------------------------------------ = 1.8668 * 10^23 molecules 1 mole because there are 3 sig figs the answer should reflect that number. so the answer is 1.87 * 10^23 molecules
Bromine, Br2, is a diatomic molecule that is liquid.
To find the number of bromine molecules in the flask, first determine the molar mass of bromine, which is 79.904 g/mol. Then, use Avogadro's number (6.022 x 10^23 molecules/mol) to convert the mass of bromine in the flask to the number of molecules. This will give you approximately 1.66 x 10^22 bromine molecules in the flask.
Bromine
Bromine is a liquid at room temperature because it has weak intermolecular forces between its molecules. These weak forces allow bromine molecules to easily slide past each other, giving the substance its liquid state.
Bromine is the only element that is liquid and forms diatomic molecules Br2. Mercury is also an element and is liquid but is monoatomic.