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If you had 100 g of compound, then...
76.9 g CaSO3 x 1 mol/120 g = 0.64 moles CaSO3
23.1 g H2O x 1 mol/18 g = 1.28 moles H2O
mole ratio is 1.28 moles H2O per 0.64 moles CaSO3 or 2 to 1.
So the formula of the compound would be CaSO3-2H2O

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Q: Calculate the formula for the following hydrate composed of 76.9percent CaSO3 and 23.1percent H2O.?
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