The formula mass of potassium sulfide, K2S is 2(39.1)+32.1=110.3
1 mole of potassium sulfide has a mass of 110.3g
Mass of 3.3mol of K2S = 3.3 x 110.3 = 364g
Potassium Sulfide - K2S2 Potassium1 SulfurPotassium = 39 grams per moleSulfur = 32 grams per moleAdd up the total mass - 2 K's and 1 S:2(39) + 1(32) = 110 grams/moleNow just make sure the units cancel so that you can multiply or divide out the mole unit3.3 mole K2S x 110 grams K2S/molemole unit cancels and you're left with 363 grams K2S
You did not describe the amount of potassium bicarbonate amount in grams in your question. But if you are about 1 gram of potassium bicarbonate it will be 0.0099 moles in one gram of potassium bicarbonate. 0.0199 moles in 2 grams of potassium bicarbonate.
To calculate the grams of potassium permanganate in 2.20 moles, you would need to know the molar mass of potassium permanganate. The molar mass of potassium permanganate (KMnO4) is about 158.034 g/mol. So, 2.20 moles of KMnO4 is equal to 2.20 moles x 158.034 g/mol = 347.67 grams of potassium permanganate.
To find the number of moles, you first need to calculate the molar mass of potassium (39.10 g/mol). Then, divide the given mass (449g) by the molar mass to get the number of moles. In this case, 449g of potassium would contain approximately 11.5 moles.
To find the number of moles in 245g of potassium bromide, first calculate the molar mass of KBr by adding the atomic masses of potassium (39.10 g/mol) and bromine (79.90 g/mol). The molar mass of KBr is 119.00 g/mol. Then, divide the given mass by the molar mass: 245g / 119.00 g/mol = 2.06 moles of potassium bromide.
Potassium Sulfide - K2S2 Potassium1 SulfurPotassium = 39 grams per moleSulfur = 32 grams per moleAdd up the total mass - 2 K's and 1 S:2(39) + 1(32) = 110 grams/moleNow just make sure the units cancel so that you can multiply or divide out the mole unit3.3 mole K2S x 110 grams K2S/molemole unit cancels and you're left with 363 grams K2S
You did not describe the amount of potassium bicarbonate amount in grams in your question. But if you are about 1 gram of potassium bicarbonate it will be 0.0099 moles in one gram of potassium bicarbonate. 0.0199 moles in 2 grams of potassium bicarbonate.
The molar mass of potassium (K) is approximately 39.1 g/mol. Using this molar mass, we can calculate the weight of 35.1 moles of potassium by multiplying the molar mass by the number of moles. Therefore, 35.1 moles of potassium would weigh approximately 1371.41 grams.
To calculate the grams of potassium permanganate in 2.20 moles, you would need to know the molar mass of potassium permanganate. The molar mass of potassium permanganate (KMnO4) is about 158.034 g/mol. So, 2.20 moles of KMnO4 is equal to 2.20 moles x 158.034 g/mol = 347.67 grams of potassium permanganate.
To calculate the number of moles of potassium chloride in a 100.0g sample, you need to divide the mass of the sample by the molar mass of potassium chloride. The molar mass of potassium chloride is approximately 74.55 g/mol. Therefore, 100.0g ÷ 74.55 g/mol = approximately 1.34 moles of potassium chloride in the sample.
To find the number of moles, you first need to calculate the molar mass of potassium (39.10 g/mol). Then, divide the given mass (449g) by the molar mass to get the number of moles. In this case, 449g of potassium would contain approximately 11.5 moles.
To calculate the mass of 2x10^12 atoms of potassium, you first need to find the molar mass of potassium (39.10 g/mol). Then, divide the number of atoms by Avogadro's number to get the moles of potassium. Finally, multiply the moles by the molar mass to find the mass in grams, which in this case would be 0.01566 grams.
To calculate the volume, first find the number of moles of potassium hydroxide using its molar mass. Then use the molarity to calculate the volume. Calculate moles of KOH: 10.7g / 56.11g/mol = 0.191 moles KOH Volume = moles / Molarity = 0.191 moles / 0.550 mol/L = 0.348 L = 348 mL
For this you need the atomic (molecular) mass of KCl. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. KCl= 74.6 grams50.0 grams KCl / (74.6 grams) = .670 moles KCl
The separate components of this compound, potassium hydrogen phthalate are one potassium, five hydrogen, eight carbon and four oxygen atoms. The total molar mass is then 204.221 grams per mole.
To determine the grams of potassium chloride formed, you first need to calculate the moles of oxygen produced by the decomposition of potassium chlorate. Then, use the stoichiometry of the balanced chemical equation to convert moles of oxygen to moles of potassium chloride. Finally, from the molar mass of potassium chloride, you can calculate the grams formed.
To calculate the grams of potassium bromite in 0.280 moles, you would multiply the number of moles by the molar mass of KBrO2, which is 119 g/mol. Therefore, 0.280 moles of KBrO2 would be 0.280 moles * 119 g/mol = 33.32 grams.