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Determine the empirical formula for the following a compound made from 5.93 percent hydrogen by mass and 94.07 percent oxygen by mass with a total molar mass of 34.02 g?
Crazygal992
Firstly divide percentages by molar mass of that element
H
5.93/1.01=5.87
O
94.07/16=5.88
Then divide the result of the first step by the smallest answer
H
5.87/5.87=1
O
5.88/5.87=1
Empirical Formula is HO
If the molar mass is 34.02 we can divide this by our empirical formulas molar mass to get the molecular formula.
so 34.02/(1.01+16)=34.02/17.01=2
so the molecular formula is H2O2 (Hydrogen Peroxide)
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∙ 13y ago
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