For benzene, all you have to do is move the double bonds of the ring around. And for the H2NCH2+, you have 2H on the N, and then a double bond between N and C, then two H bonded to the C.
Because nitro groups are meta-directing, the product will be m-dinitrobenzene. The resonance can be shown by depicting the charge as being in the para, ortho, and meta positions.
There are 2 resonance structures for benzene.
There isn't such a thing as more aromatic. Something is aromatic or not. If you are referring to the stabilization due to aromaticity, naphthalene has more electrons in the stabilizing Pi-system is therefore more stabilized.
The benzene molecule is unsaturated but the double bonds present inside the benzene ring are delocalized due to bond resonance (pi structure). This makes the double bonds of benzene much less reactive then more discreet double bonds (as in ethylene). This structure makes it behave more like a saturated compound, preferring substitution reactions over addition reactions. It is resistant to addition reactions across the double bond because such a reaction reduces the resonance stabilization energy. However, when reactions do occur, resonance stability is almost always re-established (Birch Reduction reactions are exceptions. See related link).
No, H2O does not have a possible resonance structures.
Thermocol is another name for polystyrene (PS), which is a type of plastic. Benzene is an industrial solvent, and it's primary use is to make styrene. The chemical structure of benzene, a non-polar organic hydrocarbon solvent, and of PS is such that benzene will dissolve styrene and polystyrene.
There are 2 resonance structures for benzene.
Yes!
Benzene has a property called resonance. Because of this, the three pi-bonds in benzene act as a rather delocalized single pi-structure. So, benzene does not actually have 3 distinct pi-bonds. This pi-structure is stable, which explains why benzene is more stable than it would be if it had 3 pi-bonds.
This is a tough question. Virtually every Organic chemistry teacher will say 2....the two Kekule resonance structures. However....that is incorrect. Benzene also has 4 other minor resonance forms. Mathematical calculations, as well as quantum mechanics have shown conclusively that benzene is not 2 sole resonance canonicals....but the Dewar structures as well. My proof is this....the bond order is not 1.5, as predicted....but rather 1.463. Hope this helps. Dr Jim Romano CEO Romano Scientific CEO Orgoman.com
because of resonance
c-c bond length in benzene is 1.397 angston and that of ethene is 1.34 angston structure of benzene is a resonance hybrid, therefore all the c-c bond lengths are equal but different from those in alkanes,alkenes, and alkynes.
The cation formed upon addition of an electrophile to benzene is highly stabilized by resonance,whereas the cation formed to an alkene is stabilized by hyperconjugation. The loss of a proton in benzene is favourable due to the restoration of the cyclic pi-system.
Resonance structure of butadiene explains H2C. This is known as carbon and hydrogen.
sp^2 Due to 3 pi bonds, In reality a single pi 'cloud' of 6 delocalised electrons exists around the ring (refer to resonance structure).
ACETONE IS. BENEZE is quiet stability as a result of resonance
There isn't such a thing as more aromatic. Something is aromatic or not. If you are referring to the stabilization due to aromaticity, naphthalene has more electrons in the stabilizing Pi-system is therefore more stabilized.
The actual structure