0
What else can I help you with?
What mass of nitrogen in grams is present in 148 grams of ammonium sulfate?
Ammonium sulfate contains 21% nitrogen by mass. To find the mass of nitrogen in 148 grams of ammonium sulfate, you would first calculate 21% of 148 grams, which equals 31.08 grams of nitrogen.
Where can you find ammonium sulfate?
Ammonium sulfate, (NH4)2SO4, is a common type of fertilizer. It can be found in packaged fertilizer at nurseries or in the nursery section of department stores. This product is available in bulk to farmers. A truck load or rail car full can be had in the commercial market. A link can be found below.
How many moles of ammonium ions are in 6.965 of ammonium carbonate?
To find the number of moles of ammonium ions, we first calculate the molar mass of ammonium carbonate (NH4)2CO3. It is 96.086 g/mol. Then we can find the moles of (NH4)2 cations in 6.965 g by dividing the mass by the molar mass. This gives us 0.0726 moles of ammonium ions.
How many moles of ammonium ions are in 6.965 g of ammonium carbonate?
To find the number of moles of ammonium ions in 6.965 g of ammonium carbonate, you first need to calculate the molar mass of ammonium ions, which is 18.0399 g/mol. Then, divide the given mass by the molar mass to find the number of moles. So, 6.965 g / 18.0399 g/mol = 0.386 moles of ammonium ions.
How many moles of ammonium ions does a 22.5 gram sample of ammonium carbonate?
To calculate the number of moles of ammonium ions in a 22.5 gram sample of ammonium carbonate, you need to first determine the molar mass of ammonium carbonate. Then, divide the given mass by the molar mass to find the number of moles. After that, since there are 2 ammonium ions in one molecule of ammonium carbonate, you will need to multiply the result by 2 to determine the number of moles of ammonium ions.
What mass of nitrogen in grams is present in 148 grams of ammonium sulfate?
Ammonium sulfate contains 21% nitrogen by mass. To find the mass of nitrogen in 148 grams of ammonium sulfate, you would first calculate 21% of 148 grams, which equals 31.08 grams of nitrogen.
What is the percent on nitrogen in ammonium hydrogen sulfate?
Ammonium hydrogen sulfate, (NH4)HSO4, contains one nitrogen atom in the ammonium ion. To calculate the percentage of nitrogen by mass, you would find the molar mass of nitrogen in the compound and divide it by the molar mass of the entire compound, then multiply by 100 to get the percentage.
How many moles of ammonium sulfate are in 150g sample?
To find the number of moles of ammonium sulfate in a 150g sample, you first need to calculate the molar mass of ammonium sulfate (NH4)2SO4, which is approximately 132.14 g/mol. Then, divide the given mass (150g) by the molar mass to get the number of moles, which would be approximately 1.14 moles.
When 300g of ammonia reacted with excess sulfuric acid to produce ammonium sulfate 985 g of product were obtained what is the percent yield of ammonium sulfate for this reaction?
The theoretical yield of ammonium sulfate can be calculated based on the amount of ammonia used. To find the percent yield, divide the actual yield (985 g) by the theoretical yield and multiply by 100. Percent yield = (actual yield / theoretical yield) x 100.
What mass of ammonium sulphate is required to produce 0.5 liters of mole solution?
To determine the mass of ammonium sulfate needed to make a 0.5 M solution: Calculate the molar mass of ammonium sulfate (NH4)2SO4. Use the formula: Mass (g) = Molarity (M) x Volume (L) x Molar mass (g/mol). Plug in the values: Molarity = 0.5 M, Volume = 0.5 L, and Molar mass of (NH4)2SO4. Calculate to find the mass of ammonium sulfate required.
Where can you find ammonium sulfate?
Ammonium sulfate, (NH4)2SO4, is a common type of fertilizer. It can be found in packaged fertilizer at nurseries or in the nursery section of department stores. This product is available in bulk to farmers. A truck load or rail car full can be had in the commercial market. A link can be found below.
What is the normality of 37 percent fuming HCl?
To find the normality of a solution, you need to know the molarity and whether the solution is monoprotic or polyprotic. Since fuming HCl is typically monoprotic (one hydrogen per molecule), you can assume the normality is equal to the molarity. Therefore, the normality of a 37% fuming HCl solution is approximately 11.1 N (since 37% is roughly 11.1 M HCl).
Where can one find information on ammonium?
One can find information on ammonium from the following sources: Extension, ND Health, Walmart, About Chemistry, New York Times, Wikipedia, Ammonium Nitrate.
How many grams of ammonium sulfate (MW 132.1) are needed to make 1.5 L of an 8 M solution?
Use the compbined equation mass(g) / Mr = [conc] x vol(mL) / 1000 ( = moles) Algebraically rearrange mass(g) = Mr X [conc] x vol(mL)/1000 Substituting mass(g) = 132.1 x 8Mol/L x 1500 mL/ 1000 = 1585.2 g or 1.5852 kg NB The '1000' is used to convert the units of L(itres) in 'M' to mL.
How many sulfate ions are in a 375.0 gram sample of Iron 3 Sulfate?
In iron (III) sulfate, the ratio of iron to sulfate ions is 1:2. This means that for every one mole of iron (III) sulfate, there are three moles of sulfate ions. To find the number of sulfate ions in a 375.0 gram sample of iron (III) sulfate, you would first calculate the number of moles of iron (III) sulfate, and then multiply that by three to find the number of sulfate ions.
How many moles of ammonium ions are in 6.965 of ammonium carbonate?
To find the number of moles of ammonium ions, we first calculate the molar mass of ammonium carbonate (NH4)2CO3. It is 96.086 g/mol. Then we can find the moles of (NH4)2 cations in 6.965 g by dividing the mass by the molar mass. This gives us 0.0726 moles of ammonium ions.
What is the molecular mass of ammonium sulfate?
Ammonium sulphate, (NH4)2SO4, is not a molecular compound. It is a an ionic compound with a formula unit. The mass of the formula unit is determined by doing the following: N: 2 x 14.0067g = 28.0134g H: 8 x 1.00974g = 8.06352g S: 1 x 32.065g = 32.065g O: 4 x 15.9994g = 63.9976g _______________________ Total mass 132.140g The mass of one formula unit of is 132.140g.
