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Ammonium sulphate, (NH4)2SO4, is not a molecular compound. It is a an ionic compound with a formula unit. The mass of the formula unit is determined by doing the following:
N: 2 x 14.0067g = 28.0134g
H: 8 x 1.00974g = 8.06352g
S: 1 x 32.065g = 32.065g
O: 4 x 15.9994g = 63.9976g
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Total mass 132.140g
The mass of one formula unit of is 132.140g.
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What is the atomic mass of sulfate?
There is no atomic mass - sulfate is a polyatomic ion. The molecular mass, however, is 80.1 g/mole.
What is the molecular mass of NaHSO4?
The molecular mass of NaHSO4 (sodium hydrogen sulfate) is approximately 120.06 g/mol.
Whats the observation for ammonium sulfate?
The chemical formula of ammonium sulfate is (NH4)2SO4.
The molecular mass of a compound is 63.008 amu contains Hydrogen and Oxygen and Nitrogen elements It molecular formula is?
The molecular formula of the compound is NH4NO3, which is ammonium nitrate. This compound contains nitrogen, hydrogen, and oxygen elements, with a molecular mass of approximately 63.008 amu.
What is the relative molecular mass ammonium?
The ammonium ion has one nitrogen atom and four hydrogen atoms. Their atomic masses are 14 and 1 respectively. Therefore the RMM of the ammonium ion s 14+4x1=18.
What is the molecular formula for ammonium sulphate?
The molecular formula for Ammonium Sulphate is (NH4)2SO4.
What is the weight in grams of 1 mole of ammonium sulfate (NH4)2SO4?
The molar mass of ammonium sulfate is 132,14 g.
Is ammonium sulfate molecular?
No. Ammonium sulfate is an ionic compound with the formula unit of (NH4)2SO4. Both the ammonium ion, NH4+, and the sulfate ion, SO42- are polyatomic ions.
What mass of nitrogen in grams is present in 148 grams of ammonium sulfate?
Ammonium sulfate contains 21% nitrogen by mass. To find the mass of nitrogen in 148 grams of ammonium sulfate, you would first calculate 21% of 148 grams, which equals 31.08 grams of nitrogen.
Mass of 1.60 mol of ammonium sulfate?
you take the molar mass of ammonium sulfate (132.144) and multiply that by the 1.60 moles you are already given to get the answer, 211.4034 grams the equation looks like this: 132.144*1.60=211.4304 g
What is the molicular formula and molicular mass of ammonium oxalate?
Formula : (NH4)2C2O4 Molar mass : 124
What is the percent of nitrogen in ammonium sulfate?
The chemical formula of Ammonium sulfate is (NH4)2SO4. The first step to these problems is finding all the atomic weights of the elements involved (including how many atoms of each element there is) and then adding them all up to get the total molecular mass of ammonium sulfate.Nitrogen = 14.0 × 2 = 28.0 gramsHydrogen = 1.00 × 8 = 8.00 gramsSulfur = 32.1 gramsOxygen = 16.0 × 4 = 64.0 grams-------------------------------------------Ammonium sulfate = 132.1 gramsThen to figure out the percentage of nitrogen in the compound, take the total mass of nitrogen and divide it by the total mass.Mass of nitrogen ÷ mass of ammonium sulfate = % nitrogen28.0 ÷ 132.1 = .212 = 21.2% nitrogen in ammonium sulfate(NH4)2SO4Percentage nitrogen by mass=(Molar mass of nitrogen)/(Molar mass of ammonium sulfate)*100In ammonium sulfate there are 2 Nitrogens, 8 Hydrogens, 4 Oxygens and 1 Sulfur, and their molar masses are 14, 1, 16 and 32 respectively. So, by dividing the molar mass of nitrogen in the compound by the total molar mass of the compound and multiplying it by one hundred we get the percentage of nitrogen.(14*2)/(14*2+1*8+16*4+32)*100= 21.2121...=21%
Anion for ammonium sulfate?
The anion for ammonium sulfate is sulfate (SO4^2-). Ammonium sulfate is a salt that consists of the ammonium cation (NH4^+) and the sulfate anion.
What is the weight in grams of 1 mole of ammonium sulfate NH42 SO4?
The molar mass of ammonium sulfate, (NH4)2SO4, is 132.14 g/mol. Therefore, 1 mole of ammonium sulfate weighs 132.14 grams.
What is the mass of 0.45 mol of ammonium sulfate?
To calculate the mass of 0.45 mol of ammonium sulfate (NH4)2SO4, you need to know its molar mass. The molar mass of (NH4)2SO4 is 132.14 g/mol. Multiply the number of moles (0.45 mol) by the molar mass to get the mass: 0.45 mol x 132.14 g/mol = 59.46 grams. Therefore, the mass of 0.45 mol of ammonium sulfate is 59.46 grams.
What mass of ammonium sulphate is required to produce 0.5 liters of mole solution?
To determine the mass of ammonium sulfate needed to make a 0.5 M solution: Calculate the molar mass of ammonium sulfate (NH4)2SO4. Use the formula: Mass (g) = Molarity (M) x Volume (L) x Molar mass (g/mol). Plug in the values: Molarity = 0.5 M, Volume = 0.5 L, and Molar mass of (NH4)2SO4. Calculate to find the mass of ammonium sulfate required.
What is the percentage by mass of nitrogen in ammonium sulphate?
Ammonium sulfate has the chemical formula (NH4)2SO4. The molar mass of nitrogen is 14.01 g/mol and the molar mass of (NH4)2SO4 is 132.14 g/mol. Therefore, the percentage by mass of nitrogen in ammonium sulfate is (2*14.01)/(132.14) * 100% = 21.2%.
