Add 50 mL of HCl 1 N in a 1 L volumetric flask, class A or B; add ca. 900 mL distilled water to the flask. Place the flask in a thermostat at 20 0C. After 30 min add slowly distilled water to the mark (1 L) and stir well the closed flask. Pour the solution in a bottle. Place a label with the date, concentration, name of the solution on the bottle.
g HCl solution = 2500 mL of HCl * 1 liter/1000 mL * 1190 g/L = 2975 g 37% solution (37 g HCl/100 grams of solution) gives you the grams of HCl: g HCl = 0.37 * 2975 g = 1100.8 g HCl Moles HCl = 1100.8/(36.46 g/mole) = 30.2 moles Therefore the molarity, which equals the normality in this case = 30.2 moles/2.5 L = 12.07 M = 12.07 N If you want to make 100 mL of a 0.1 N solution, Volume of HCl solution needed = (0.1 N * 100 mL) /12.07 N = 0.83 mL Take 0.83 mL of the 37% HCl, and dilute it with water to 100 mL.
Ah, preparing a 0.02 M solution of HCl is a wonderful journey. Simply measure out the correct amount of hydrochloric acid and dilute it with water until you reach the desired concentration. Remember to handle chemicals with care and always wear appropriate safety gear. Happy experimenting, my friend!
Ciprofloxacin is more soluble in 0.1 N HCl solution compared to water. The solubility of ciprofloxacin increases in acidic solutions like HCl due to its acidic nature, which helps to increase its solubility in the 0.1 N HCl solution.
The pH of a 0.280 M HCl solution is approximately 0.55. This is because HCl is a strong acid that dissociates completely in solution to produce H+ ions, leading to a low pH value.
To find the volume of the 2.00 M HCl stock solution needed, we use the formula M1V1 = M2V2. Rearranging for V1 gives us V1 = (M2 * V2) / M1, where M2 is the desired concentration (0.50 M), V2 is the final volume (150 mL), and M1 is the stock concentration (2.00 M). Plugging in the values gives V1 = (0.50 M * 150 mL) / 2.00 M = 37.5 mL. You will need 37.5 mL of the 2.00 M HCl stock solution to make a 150 mL solution of 0.50 M HCl.
To make a 1% HCl solution from a 35% HCl solution, you would need to dilute the concentrated solution with water. The ratio of concentrated HCl to water would be approximately 1:34. So, to make 1% HCl, you would mix 1 part of the 35% HCl solution with 34 parts of water.
To make 0.25N HCl from 1.00N HCl, you would need to dilute the 1.00N HCl solution by adding three parts of water for every part of the original solution. For example, you can mix 1 mL of 1.00N HCl with 3 mL of water to obtain 0.25N HCl solution.
To prepare a 0.2N HCl solution from 1.0N HCl, you can dilute the 1.0N HCl solution by adding 4 parts of water to 1 part of the 1.0N HCl solution. This means combining 1 volume of 1.0N HCl with 4 volumes of water to obtain the desired 0.2N HCl solution.
To convert make a dillute solution from a concentrated one, take the amount of moles needed for the final solution as mL of concetrated solution, and dillute with water until the desired volume is reached.
To prepare a 10mM solution of Tris-HCl, you would weigh out the appropriate amount of Tris-HCl powder using a balance and dissolve it in water to make a final volume of solution. For example, to make 1L of 10mM Tris-HCl solution, you would need to dissolve 0.121g of Tris-HCl in 1L of water.
To prepare 1 M hydrochloric acid (HCl) solution, you usually need to dilute concentrated HCl solution (~35-37% HCl) with water in a specific ratio. The specific volume of concentrated HCl needed depends on its concentration and the final volume of the 1 M solution you want to make. In this case, 85 ml of concentrated HCl is likely to be the volume needed to make 1 L of 1 M HCl solution.
To make a 0.1M solution from a 1M HCL solution, you would dilute the 1M HCL with 10 parts of water (or whatever solvent you are using). For example, mix 1 mL of 1M HCL with 9 mL of water to obtain a 0.1M HCL solution.
No, a 38% HCl solution is not the same as a 12N HCl solution. The concentration of a solution is based on the amount of solute dissolved in a specific volume of solvent. A 38% HCl solution means there is 38 grams of HCl in 100 mL of solution, while a 12N HCl solution means there are 12 moles of HCl in one liter of solution.
To standardize 1N HCl (hydrochloric acid), you would typically use a primary standard base, such as sodium hydroxide (NaOH), of known concentration to titrate the HCl solution. By carefully titrating the HCl with the NaOH, you can determine the exact concentration of the HCl solution. This information can then be used to adjust the concentration of the HCl solution as needed to make it accurately 1N.
To make a 250 mL 0.1 M HCl solution, you will need to dilute the 12.1 M solution. Use the formula C1V1 = C2V2, where C1 is the initial concentration, V1 is the volume of the initial solution, C2 is the final concentration, and V2 is the final volume. Plugging in the values, you would need to add approximately 20.7 mL of the 12.1 M HCl solution to make the 0.1 M HCl solution.
Amount of HCl is 500cm^3 of .8M HCl = .8 x 500/1000 = 0.4 mol. Volume of 10M acid to give 0.4 mol = .4/10 = 0.04dm^3 = 40cm^3 Add 500 - 40 = 460 cm^3 of water. Caution : 10M HCl is highly corrosive and should be handled with care.
The pH of a 6M HCl solution is 0.