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2.538g in 1000ml.
If you are making this for a titration, like for SO2 or thiosulfate, you need also to add iodide:
1. dissolve 8 g potassium iodide in about 250 mL water.
2. add 2.538 g iodine to the water solution. Stir until dissolved.
3. transfer to a 1000 mL volumetric flask and Q.S. to 1000 mL
You should standardize vs. thiosulfate or arsenious oxide.
What else can I help you with?
What is the reason behind using 40 g of potassium iodide and 12.7 g of iodine to prepare 0.1 N of iodine?
- The atomic weight of iodine is 126,90447; for a 0,1 N solution, dividing by 10 the result is 12,69. - The iodide (KI) is added to increase the solubility of iodine in water or alcohol.
What is Iodine value for Activated Carbon?
Iodine Value of Activated Carbon Apparatus: Volumetric flask, conical flask, beaker, burette, pipette, filter paper Reagents: * 0.1N Iodine solution ( 40 gm KI in 1 Ltr of Distilled water ). * 0.05N Sodium Thiosulphate solution (12.5 gm Na2S2O3.5H2O in 1 Ltr Distilled water) * 1% Starch solution * Activated carbon Procedure: I Standardisation of Iodine solution * Take 10c.c of 0.1N Iodine solution in conical flask. * Add 2 drops of Starch solution. * The pale yellow colour of Iodine Soln turns Blue. * Titrate with 0.05 N Sodium Thiosulphate till it becomes Colourless. * Burette reading corresponds to blank reading.(B) II * Weigh very accurately 0.2 gm of Activated carbon * Introduce it into the Iodine flask which should be completely dry * Add 40cc of 0.1N Iodine solution * Shake the flask for 4 minutes and filter it * Collect the filterate in a dry flask and Titrate 10cc of the filtrate against Standard Sodium thiosulphate solution using starch as indicator * Burette reading corresponds to (A) Calculations: Iodine value: C x Conversion factor; mg/gm Factor:Mol wt. of iodine (127) x normality of iodine x 40 / Wt. of carbon x Blank reading C=B-A This is dry basis test From Ishan Udyog Bhilai
How do you prepare 200 ml of 0.1 N ethyl acetate?
Prepare 200 ml of 0.1 N / 0.1 M Ethyl Acetate1.96 ml pure ethyl acetate (M.W. 88.1, Sp. Gr. 0.9005 g/ml at 20°C) and make it up to 200 ml volume with distilled water.Your solution will be ready....
Prepare 500ml of 0.12N HCL solution?
To prepare 500ml of 0.12N HCl solution, you will need to dilute a concentrated hydrochloric acid solution. To do this, measure out 2.5ml of concentrated HCl (37% w/w) and dilute it to 500ml with distilled water. Be sure to wear appropriate safety equipment and handle the acid with caution.
What is the chemical name for Nitrogen Hydrogen and Iodine?
if by chemical name you mean element then: Nitrogen = N Hydrogen = H Iodine = I
How many grams of iodine would you weigh out to prepare 50 mL of a 0.200 N iodine solution?
To calculate the mass of iodine needed to prepare a 0.200 N solution in 50 mL, you can use the formula: Mass (g) = molarity (mol/L) * volume (L) * molar mass (g/mol). First, convert 50 mL to L (50 mL = 0.050 L). Then, substitute the values: Mass (g) = 0.200 mol/L * 0.050 L * 253.8 g/mol = 2.538 g of iodine. Therefore, you would weigh out 2.538 grams of iodine.
How do you make 1 liters of 0.02 N iodine solution?
To prepare 1 liter of a 0.02 N iodine solution, first calculate the amount of iodine (I2) needed. Since the normality of the solution is based on the equivalent weight of iodine, and considering that 1 equivalent of iodine corresponds to 1 mole of I2, you need 0.02 equivalents in 1 liter. This translates to 0.02 moles of I2, which is approximately 5.12 grams (molar mass of I2 is about 253.8 g/mol). Dissolve this amount of iodine in enough distilled water to make a final volume of 1 liter.
What is the reason behind using 40 g of potassium iodide and 12.7 g of iodine to prepare 0.1 N of iodine?
- The atomic weight of iodine is 126,90447; for a 0,1 N solution, dividing by 10 the result is 12,69. - The iodide (KI) is added to increase the solubility of iodine in water or alcohol.
Who to calculated normality of iodine?
Normality of iodine ((I_2)) can be calculated using the formula: Normality = Molarity x n, where n is the oxidation state of iodine in the reaction. For example, if you are using a 0.1 M (I_2) solution in a redox reaction where iodine is being reduced to iodide ions ((I^-)), then the normality of iodine would be 0.1 N.
How do you prepare 1 N ferrous ammonium sulphate?
To prepare 1 N ferrous ammonium sulfate solution, dissolve 392.15 g of the compound in distilled water and dilute to 1 L. This will yield a solution with a concentration of 1 N.
How do you prepare standard 0.1 N 100 ml Na2CO3 solution?
To prepare a 0.1 N 100 ml Na2CO3 solution, dissolve 5.3 grams of Na2CO3 in water and dilute to 100 ml. This will give you a solution with a concentration of 0.1 normal (N) for the 100 ml volume.
How do you prepare 1 N sodium bicarbonate?
To prepare a 1 N solution of sodium bicarbonate, dissolve 84 grams of sodium bicarbonate in enough water to make 1 liter of solution. This will give you a 1 N (equivalent to 1 mol/L) concentration.
How prepare 0.1 N oxalic acid?
To prepare 0.1 N oxalic acid solution, you would need to dissolve 0.634 g of oxalic acid dihydrate (H2C2O4·2H2O) in distilled water and make up the solution to a final volume of 1 liter. This will give you a 0.1 N (normality) solution of oxalic acid.
How do you Prepare 0.02 N potassium permanganate solution?
To prepare a 0.02 N potassium permanganate solution, you would need to dissolve 1.58 grams of potassium permanganate (KMnO4) in 1 liter of distilled water. This will give you a solution with a molarity of 0.02 N. Remember to wear appropriate personal protective equipment when handling potassium permanganate, as it can be harmful.
How do you prepare 0.5 N acetic acid solution?
To prepare a 0.5 N acetic acid solution, first calculate the molarity needed using the formula Molarity (M) = Normality (N) x Equivalent weight. Then, use this information to dissolve the appropriate amount of acetic acid in water to make 1 liter of solution. Finally, adjust the volume with water as needed.
How many grams of iodine dissolved in water for 0.02 n iodine?
To calculate the grams of iodine dissolved in water for 0.02 N iodine, you need the molar mass of iodine, which is approximately 254 g/mol. With this information, you can use the formula: Grams = Normality (N) * Equivalent weight. Therefore, for 0.02 N iodine: Grams = 0.02 * 254 = 5.08 grams of iodine.
How do you prepare 0.1 N solution HCL from 1N?
Add 100 mL of HCl 1 N in a 1 L volumetric flask, class A or B; add ca. 850 mL distilled water to the flask. Place the flask in a thermostat at 20 0C. After 30 min add slowly distilled water to the mark (1 L) and stir well the closed flask. Pour the solution in a bottle. Place a label with the date, concentration, name of the solution on the bottle.
