How do you prepare the sodium perchlorate solution and how will it behave in hydrochloric acid medium?

Answer 1

ANSWER I beg to differ that it does react in a HCl solution. But not the way the other guy said. NaClO4 + 8HCl = NaCl + 4Cl2 + 4H2O Similarly to the way bleach reacts with HCl. ---- Add the compound sodium perchlorate to water and let it dissolve. See the Related Questions link about how to prepare a solution.

The sodium perchlorate will not react or be affected by the presence of HCl in the solution.

ANSWER I beg to differ that it does react in a HCl solution.

First lets look at the actual elements within this compound. Sodium perchlorate is NaClO4 and hydrochloric acid is HCl. Then look at the structure of each, which wikipedia has very good structures. Knowing how atoms and elements act with each other. You can see that the oxygen is very reactive due to its negative charge and only has one bond to the Cl, so, it wants to complete the 'octet rule'. Thus, it picks up the hydrogen from the HCl. This completes its octet rule and has no charge. Cl then is incomplete, making it reactive, thus, taking sodium to complete its octet rule. So all in all, this reaction creates Salt (NaCl) and percholric acid (HClO4)

Here's the equation to clarify: NaClO4 + HCl -> NaCl + HClO4

Hope this helps! ---- I have serious problems with the chemistry described above!

As no new compounds are formed (all species are present in ionic form as soon as they dissolve and remain so until evaporated) the original answer is correct. And the chlorine atoms bonded to the central oxygen in the perchlorate ion each have a full compliment of 8 electrons. As well each oxygen has a full compliment of 8 electrons (two lone pairs plus two shared pairs). There is no rearrangement of electrons in the dissolving of NaClO4 in HCl(aq).