The chlorine atom is in group 17 of the Periodic Table of elements, so it has 10 inner electrons and 7 outer "valence" electrons. In forming the chloride ion, it becomes negatively charged by gaining an additional electron in the outer shell, so the valence electron shell now has 8 electrons, as per the octet rule.
The octet rule states that atoms tend to gain, lose, or share electrons to achieve a stable electron configuration with 8 electrons in their outermost shell. Sodium has 1 electron in its outermost shell, so it tends to lose this electron to achieve a stable electron configuration, forming a sodium ion with a +1 charge.
PF5 obeys the octet rule as it has 5 bonding pairs of electrons around the central phosphorus atom, satisfying the octet. Cs2 does not follow the octet rule as Cs is in Group 1 and can only form ionic bonds. BBr3 is an exception to the octet rule as boron has only 6 electrons around it due to the empty d orbital. CO3 2- also obeys the octet rule as each oxygen atom has a complete octet.
Sodium (Na) has 1 electron in the 3s orbital and chlorine (Cl) has 7 electrons in the 3p orbital. Sodium gives away the one electron to Cl, leaving it with 8 electrons (octet) in the 2p orbital (like Neon). The chlorine takes that one electron giving it 8 electrons (octet) in the 3p orbital. The sodium then has a +1 charge, and the chloride ion now has a -1 charge. This is an ionic bond.
Chlorine (Cl) would gain an electron in sodium chloride (NaCl) to achieve a full outer electron shell and attain a stable octet configuration, following the octet rule. By gaining an electron, chlorine becomes a chloride ion with a full outer shell, creating an ionic bond with the sodium cation to form a stable compound.
Yes, it does.
The octet rule is a rule in chemistry where elements want to form bonds to attain 8 electrons in their valence shell. An example of this would be sodium chloride. Bonds that don't have 8 electrons in their valence shell don't follow this rule
Yes, the octet rule states that atoms tend to gain, lose, or share electrons in order to have a full outer shell with eight electrons, which is considered stable. This stability is achieved by achieving the electron configuration of a noble gas.
yes PCl3 obey octet rule there are 5 electrons in the valence shell of phosphorous it need 3 electron to complete its octet so it form bond with 3 chlorine after bond formation there are 8 electron in its octet it obey octet rule
Az important rule: any octet has to have eight parts, otherwise it is not an octet.
The octet rule states that atoms tend to gain, lose, or share electrons to achieve a stable electron configuration with 8 electrons in their outermost shell. Sodium has 1 electron in its outermost shell, so it tends to lose this electron to achieve a stable electron configuration, forming a sodium ion with a +1 charge.
no it does not follow octet rule
No chlorine oxides will obey the octet rule.
NH3 is not an exception to the octet rule. Nitrogen (N) in NH3 has a total of 8 valence electrons (5 from nitrogen and 3 from hydrogen), fulfilling the octet rule. Nitrogen has 3 bonded pairs and 1 lone pair of electrons, following the octet rule.
BCl3 is the formula for Boron Chloride. As a matter of interest it does not obey the octet rule. It is also called a Lewis Acid.
Hydrogen is the atom that doesn't always obey the octet rule. It only needs 2 electrons to have a full outer shell, rather than the 8 electrons typically required by the octet rule. Oxygen and bromine usually follow the octet rule.
The octet rule is a chemical rule that states that atoms tend to combine in such a way that each one has a full outer electron shell of eight electrons. This stable electron configuration is similar to the noble gases, which have a full valence shell. It helps predict and explain the formation of chemical bonds.
Yes, iodine can exceed the octet rule and have an expanded octet due to its ability to accommodate more than eight electrons in its valence shell.