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Molecular formula is; C6H10OS2, so; ( I will use name as formula is long )
7.00 milligrams allicin (1 gram allicin/1000 milligrams)(1 mole allicin/162.28 grams)(2 mole S/1 mole allicin)(6.022 X 10^23/1 mole sulfur)
= 5.20 X 10^19 atoms of sulfur in 7.00 mg of anicin
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How many atoms are present in 80.0 mol of zirconium?
481,7713432.1023 atoms
How many atoms are present in Ca HCO3 2?
The number of atoms is 33.
How many atoms are present in 8.00 moles of zirconium?
48,177 134 32.1023 atoms
How many atoms of carbon are present in the reactants?
Of what reaction?
How many atoms of hydrogen are present in NH4 2S?
8
How many S atoms are present in 7.00 mg of allicin?
7,00 mg of allicin contain 0,519.10e20 sulfur atoms.
How many pounds is 700 milligrams?
700mg is about 0.0015432 pound.
How many ounces is 700 mg?
700mg = 0.0247 oz.
How many molecules of allicin are in 2.60 mg of this substance?
The molecular formula of allicin is C6H10OS2. The molar mass is 162.27 g mol−1. Use this fact along with the percentage of allicin in the substance to calculate the molecules of allicin.
How many oxygen atoms are present in a formula unit of lithium phosphate?
4 oxygen atoms are present
How many atoms are present in 8.00 mol atoms?
48,177 134 32.1023 atoms
How many atoms are present in 80.0 mol of zirconium?
481,7713432.1023 atoms
How many atoms are present in each molecule of the compound?
two atoms
How many Total no of atoms present in C12H22O11?
The total no. of atoms present in C12H22O11 is 45.
How do you tell how many atoms of iron and oxygen are present as products and how many are present as reactants in the chemical equations?
The number of atoms is indicated by coefficients.
How many atoms of hydrogen are present in the present in the reactants and in the products?
2
How many grams in 700mg?
700mg converts to 0.7g (mg divided by 1,000 = grams*).* 1 gram = 1,000mg
