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The molar mass of Silicon is 28.09g

Therefore if you have 65.6g, you divide that mass by 28.09g.

65.6g/28.09g = 2.34 mols.

For atoms, you multiply that number by 6.02 x 1023.

So 2.34 x 6.02 x 1023 = 1.41 x 1024.

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13y ago
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10y ago

According to the Periodic Table of elements, mass number of Si is 28.1.

Amount of Si = 28.09/28.1 = 1.00mol

In one mole of any element, there are 6.02 x 1023 particles (avogadro constant). Therefore 28.09g of atoms contain this number of particles.

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13y ago

65.6 grams silicon (1 mole Si/28.09 grams)(6.022 X 10^23/1 mole Si)

= 1.41 X 10^24 atoms of silicon

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13y ago

3.5 grams silicon (1mole Si/28.09 grams Si)(6.022 X 10^23/1mole Si)

= 7.5 X 10^22 atoms of silicon in 3.5 grams silicon.

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12y ago

15.6*1mol/28.09*6.022*10^23/1

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Q: How many atoms are in 65.6 g silicon?
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How many silicon atoms are there in 85.0 micrograms of silicon?

n = (8.5 x 10^-5 g) x (1 mol / 28 g) = 3.04 x 10^-6 mol N = (3.04 X 10^-6 mol) x ((6.02 x 10^23 atoms)/(1 mol)) = 1.81 x 10^18 atoms


How many grams of sand are needed to make 45 grams of silicon?

96,27 g of sand contain 45 g of silicon (if the sand is pure silicon dioxide).


How many silicon atoms are there in 1.00 g of silicon?

Silicon is a common metalloid which is a chemical element but it is considered to be tetravalent metalloid which has only 4 available electrons for covalent chemical bonding in its valence region. In the periodic table, Silicon has atomic number 14 with Si symbol. It is good to know that silicon is less reactive that Carbon-14 based on its position in the periodic table which is in the bottom of Carbon. The Standard Atomic Weight for Silicon is 28.0855 grams. The standard is based on the Avogadro's Constant which is 6.02214179 x 1023 mol-1. 1 mol of silicon will contains 6.02214179 x 1023 atoms of silicon. So, how many atoms are present in 1 gram of silicon? In 1 mol silicon (28.0855 grams) = 28.0855/28.0855 x 6.02214179 x 1023 = 6.02214179 x 1023 atoms In 1 gram silicon = 1/28.0855 x 6.02214179 x 1023 = 2.144217404 x 1022 atoms


How many Si atoms in 12.5 g sample of silicon?

Silicon is a common metalloid which is a chemical element but it is considered to be tetravalent metalloid which has only 4 available electrons for covalent chemical bonding in its valence region. In the periodic table, Silicon has atomic number 14 with Si symbol. It is good to know that silicon is less reactive that Carbon-14 based on its position in the periodic table which is in the bottom of Carbon.The Standard Atomic Weight for Silicon is 28.0855 grams. The standard is based on the Avogadro's Constant which is 6.02214179 x 1023 mol-1. 1 mol of silicon will contains 6.02214179 x 1023 atoms of silicon. So, how many atoms are present in 12.5 gram of silicon?In 1 mol silicon (28.0855 grams) = 28.0855/28.0855 x 6.02214179 x 1023 = 6.02214179 x 1023 atomsIn 12.5 gram silicon = 12.5/28.0855 x 6.02214179 x 1023 = 2.680271755 x 1023 atomsRead more: How_many_silicon_atoms_are_there_in_1.00_g_of_silicon


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How many silicon atoms are there in 85.0 micrograms of silicon?

n = (8.5 x 10^-5 g) x (1 mol / 28 g) = 3.04 x 10^-6 mol N = (3.04 X 10^-6 mol) x ((6.02 x 10^23 atoms)/(1 mol)) = 1.81 x 10^18 atoms


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How many silicon atoms are there in 1.00 g of silicon?

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