237g / 28 gmol-1 = 8.46mol. 8.46 x (6.02x1023) = 5.09x1024 silicon atoms.
.250 mole 7.02 ------ 28.09 = .250
Niobium has a atomic weight Ar = 92.9 g mol-1237 g / 92.9 g mol-1 = 2.55 mol
11 g x 1 mol Si/28.0855 g Si= 0.39 mol Si 205g He x 1mol He/4.002602 g He=51.2 mol He
5 g of sulfur contain 0,94.10e23 atoms.
The number of atoms is 28,099.10e23.
The atomic mass of neptunium is approximately 237 grams per mole. Since 1 mole of any element contains Avogadro's number of atoms (approximately 6.022 x 10^23 atoms), one atom of neptunium would weigh approximately 237 grams divided by Avogadro's number, which is a very tiny fraction of a gram.
.250 mole 7.02 ------ 28.09 = .250
49.1740 g (6.02 x 1023 atoms) / (91.22 g) = 3.25 x 1023 atoms
Niobium has a atomic weight Ar = 92.9 g mol-1237 g / 92.9 g mol-1 = 2.55 mol
6,687.1023 chlorine atoms
The number of atoms of lead is 6,68.10e23.
11 g x 1 mol Si/28.0855 g Si= 0.39 mol Si 205g He x 1mol He/4.002602 g He=51.2 mol He
5 g of sulfur contain 0,94.10e23 atoms.
1.45 g of a molecular compound with a molar mass of 237 represents 1.45/237 or 6.118 X 10-3 mole. Assuming that "representative particles" in the question means "molecules", this is (6.118 X 10-3){Avogadro's Number} or 3.68 X 1021 molecules.
1 mole Si = 28.0855g Si 245g Si x 1mol Si/28.0855g Si = 8.72 moles Si
The answer is 3.32*10^23 atoms
There are approximately 163,163 atoms of carbon in 0.020 g of carbon.