How many atoms are there in 6.26 g Si?

Answer 1

.250 mole

7.02

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28.09 = .250

Answer 2

You can't have 7.610 atoms of silicon - number of atoms has to be a whole number, because it's a count; a tally. Perhaps you mean how many grams would be in 7.610 moles of silicon. That would be 7.61moles x 28.1g/mol = approx. 214g Si.

Answer 3

For this problem, the Atomic Mass is required. Take the mass in grams and divide it by the atomic mass. Then multiply it by Avogadro's constant, 6.02 × 1023.

7.82 grams Si / (28.1 grams) × (6.02 × 1023 atoms) = 1.68 × 1023 atoms

Answer 4

To find the number of atoms in 6.26 g of Si, first calculate the number of moles of Si using its atomic mass (28.0855 g/mol). Then, use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles to atoms.

Answer 5

.250 mole

7.02

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28.09 = .250

Answer 6

There are 1.34×10²³ atoms. You look for the number of moles in the 6.26 g of Si, then you multiply by the Avogadro constant.

Answer 7

6.34 grams Si ( 1 mole Si/28.09 grams)(6.022 X 1023/1 mole Si)

= 1.36 X 1023 atoms of silicon

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