Niobium has a atomic weight Ar = 92.9 g mol-1
237 g / 92.9 g mol-1 = 2.55 mol
14,84 g magnesium are equivalent to 0,61 moles.
97,5 g of oxygen is equal to 5,416 moles.
978 g calcium contain 24,4 moles.
67,4 g HCl is equivalent to 1,85 moles.
29,0 g of calcium is equal to 0,723 moles.
To determine the number of moles in 237g of niobium, we need to use the molar mass of niobium, which is approximately 92.91 g/mol. By dividing 237g by the molar mass of niobium, we find that there are approximately 2.55 moles of niobium in 237g.
1.45 g of a molecular compound with a molar mass of 237 represents 1.45/237 or 6.118 X 10-3 mole. Assuming that "representative particles" in the question means "molecules", this is (6.118 X 10-3){Avogadro's Number} or 3.68 X 1021 molecules.
The formula is: number of moles = g Be/9,012.
27.4 g H2O x 1 mole/18 g = 1.52 moles
14,84 g magnesium are equivalent to 0,61 moles.
97,5 g of oxygen is equal to 5,416 moles.
978 g calcium contain 24,4 moles.
67,4 g HCl is equivalent to 1,85 moles.
29,0 g of calcium is equal to 0,723 moles.
573,28 of g of AgCI is equivalent to 4 moles.
156 g calcium is equivalent to 3,89 moles.
1 g of sodium sulfite is equivalent to 0,0079 moles.