1 mole of any substance contains 6.02x1023 representative particles. That is called Avogadro's number, and it's one of the most important constants in science. So, 3 moles of carbon would be 3 times that, which would be 18.06x1023, which simplifies to 1.806x1024 atoms.
3.85 X Avogadro's number = 2.32 X 1024 atoms, to the justified number of significant digits.
The questions asks how many moles of carbon atoms.Molar mass is defined as the mass of one mole of a substance or in this case 6.022x1023 atoms of carbon. So the molar mass for carbon is 12.0 g/mol. Therefore the number of moles of carbon atoms is just 36/12.0 = 3.0 moles of carbon.How many atoms are in 36 grams of Carbon?[36 (gC) /12.0 (gC/molC)] * 6.02*10+23 (atoms C/molC) = 1.8*10+24 atoms in 36 g Carbon
To calculate the number of carbon atoms in 2.6g of graphite, first calculate the number of moles of carbon using its molar mass (12.01 g/mol). Then, use Avogadro's number (6.022 x 10^23 atoms/mol) to determine the number of carbon atoms. This calculation will give you the number of carbon atoms in 2.6g of pure carbon as graphite.
the constant Mole (mol): 6.02 x 10^23 are how many atoms you have per mol so the answer can be 7 mol atoms or 6.02 x 10^23 atoms per mol x 7 actual answer is 4.214 X10^24 atoms in 7 mol
To find atoms in number of moles you multiply by avogadra's number (6.022x10^23) then multiply by the number of atoms, in this case it is one because carbon is a monotomic element. The answer is 9.03x10^23 atoms C
There are approximately 4.52 x 10^23 atoms in 0.750 mol of carbon monoxide. This is calculated by multiplying Avogadro's number (6.022 x 10^23 atoms/mol) by the number of moles of carbon monoxide (0.750 mol).
There are approximately 4.65 x 10^22 atoms in 0.0077 mol of carbon.
85.9 (g C) = 85.9 (g C) / 12.00 (g/mol C) = 7.158 (mol C)7.158 (mol C)*[6.022*1023 (atoms/mol C)] = 4.31*1024 C-atoms
There are approximately 5.84 x 10^21 carbon atoms in 9.7 x 10^-3 mol of carbon. This is calculated by multiplying Avogadro's number (6.022 x 10^23 atoms/mol) by the number of moles of carbon given.
3.85 X Avogadro's number = 2.32 X 1024 atoms, to the justified number of significant digits.
There are 1 mole of carbon atoms in 12g of carbon. This is because the molar mass of carbon is 12 g/mol, so 12g of carbon is equivalent to 1 mole of carbon atoms.
Diamond is made of up carbon. So, it has a molar mass of 12 g/mol. 6 g/mol / 12 g = 0.5 mol 0.5 mol * 6x10^23 atoms/mol = 3x10^23 atoms There are 3x10^23 atoms in six grams of diamond.
Glucose is 180.16 g/mol. Doing stoichiometry, this means 1.97 grams is 0.0109 mol glucose. Because there are 6 mols of carbon per 1 mol of glucose, that means there are 0.0656 mols of carbon in this sample. One mole is equivalent to 6.023 x 1023 atoms, which leads to 3.95 x 1022 carbon atoms.
The questions asks how many moles of carbon atoms.Molar mass is defined as the mass of one mole of a substance or in this case 6.022x1023 atoms of carbon. So the molar mass for carbon is 12.0 g/mol. Therefore the number of moles of carbon atoms is just 36/12.0 = 3.0 moles of carbon.How many atoms are in 36 grams of Carbon?[36 (gC) /12.0 (gC/molC)] * 6.02*10+23 (atoms C/molC) = 1.8*10+24 atoms in 36 g Carbon
There are approximately 1.34 x 10^22 carbon atoms in 1.6 g of carbon. This calculation is based on the molar mass of carbon (12 g/mol) and Avogadro's number (6.022 x 10^23 atoms/mol). To find the number of atoms, divide the mass of the sample by the molar mass of carbon, and then multiply by Avogadro's number.
There are 3 carbon atoms in 1 molecule of acetic acid (HC2H3O2). Therefore, in 0.062 mol of acetic acid, there would be 0.062 x 3 = 0.186 moles of carbon atoms. To find the number of carbon atoms, you would multiply the number of moles by Avogadro's number (6.022 x 10^23) to get approximately 1.12 x 10^23 carbon atoms.
To convert atoms of carbon to moles, you need to divide the number of atoms by Avogadro's number, which is (6.022 \times 10^{23}) atoms/mol. Thus, the calculation is: (\frac{5.73 \times 10^{24} \text{ atoms}}{6.022 \times 10^{23} \text{ atoms/mol}} \approx 9.50 \text{ mol}) of carbon.