? atoms N = 5.00g C2H5O2N x 1 mole C2H5O2N/75.08g C2H5O2N x 1 mol N/1 mol C2H5O2N x (6.022x10^23 atoms)/1 mol N = 4.01 x 10^22 atoms N
To find 75.08g:
2C 2 x 12.01g = 24.02g
5H 5 x 1.01g = 5.05g
2O 2 x 16.00g = 32.00g
1N 1 x 14.01g = 14.01g
Add the four numbers together and you get: 1 mole of C2H5O2N = 75.08 grams
You use this as a conversion factor in the problem above.
500g
You will need more than just one nickel. Most scales require you to calibrate with a specific weight, usually a weight that is close to the scales capacity (ie 500g weight for 500g capacity scale) Nickels weigh approximately 5g so you would needs lots of them. However it is not exact and you will sometimes find nickels that weigh 4.9g to 5.1g. Nickels should only be used as a last ditch effort to fix a scale that is way out of calibration. You can find cheap calibration weights for pocket scales online.
None. Changing water from 25 degrees C to 5 degrees C requires heat to be REMOVED, not added!
Assuming you mean "how much carbon dioxide is generated by the electricity consumption of a computer", you are actually asking a very complicated question.In the first instance, you need to know what the energy consumption of your/the average computer is. This depends on a huge number of factors such as: how powerful the processor and graphics cards are, how many hard drives and optical drives it has and what kind of monitor it has and what size that is. Also, the consumption varies depending on whether the computer is under load (performing calculations and reading from or writing to hard drives or optical media). If you're not interested in accuracy, I would guess about 200W for a modest office machine rough average.Next, it depends on how much CO2 is produced per unit of electricity from your supplier. This in turn depends on what sources are used to provide your energy. Coal and oil produce more CO2 than gas, nuclear and others. The calculation is likely to be very complex and require a lot of research. The answer could be in the region of 500g per KWh, but this could vary wildly depending on which country you are in.So taking our two assumptions (0.2KW and 500g/KWh), we can very roughly estimate 100g of CO2 produced per hour of computer usage.
The water and pot(/) have a temperature increase of 100-25 degrees C that is 75 degrees. the formula Q=mass * SH* change in temperature can be used for both the water and the steel pot Hence for steel pot Q=510 j/kg/degC*.5kg*75Deg C=19125 joule. For water SH=4187 j/kg/C QW= .45*4187*75=141311 joule total heat (neglecting changes and losses to get the water to 100 deg C is 160436 joule or 160.4 kjoule. Note this does not boil the water it only raises the temperature to 100 degrees C. to boil the water requires approximately a futher 1250 kJ
500g
1 kg - 500g = 500g
Roughly 500g
4.72kg-500g = -495.28
1.5kg add 500g = 501.5
500g is bigger - there are roughly 28.4 grams in an ounce, so 500g is approximately 17.6oz
500g, your welcome!
im guessing about 500g worth?
Why 500g i had one with 600g it was a wind manion and a darkus tuskore
5000 mg, 500g, 50 kg.
Slightly over. 500g = approx. 1.1 pounds.
500 g/1 kg = 500g/1000g = 0.5 = 50%