We need the specific heat capacity to calculate this. For water it's 4200 J/kg/K
For 32g, the energy per kelvin required is 4200 * 32^(-3) = 134.4 J/K
Since kelvin scale and celcius scale have then same increments, the energy required is:
134.4*(54-12) = 134.4*42
= 5644.8 J
Most people would finish here, you want calories...
5644.8 * 0.239 = 1350 cal or 1.35kcal
A fever. Normal body temperature is around 37 degrees Celsius, so 40 degrees Celsius would indicate a fever. It would be a good idea to monitor your symptoms and consult with a healthcare provider if needed.
-21 degrees Celsius to 10 degrees Celsius.
Because degrees Celsius means the same as degrees centigrade, the answer is 18 degrees. Better use the correct word "degrees Celsius."
If its in Celsius then another 13 degrees are needed because water boils at 100 degrees Celsius
Marble forms from limestone when it undergoes metamorphism from heat and pressure. The temperature needed for marble to form typically ranges from 400 to 900 degrees Celsius.
To convert 4 kg of ice at 0 degrees Celsius to steam at 100 degrees Celsius, you would need to calculate the heat required to raise the temperature of ice to 0 degrees Celsius, melt the ice to water at 0 degrees Celsius, raise the temperature of water to 100 degrees Celsius, and then convert water to steam at 100 degrees Celsius. The total amount of heat needed can be calculated using the specific heat capacities and latent heats of fusion and vaporization of water.
8.200 J
This is the latent heat of vaporisation of water, which at standard pressure, is 539 calories (per gram).
A fever. Normal body temperature is around 37 degrees Celsius, so 40 degrees Celsius would indicate a fever. It would be a good idea to monitor your symptoms and consult with a healthcare provider if needed.
(5)(3)= 15 calories. 1 calorie is the energy (heat) to raise 1 gram of water by 1 degree celsius, so 5 grams of water (3 degrees Celsius) = 15.
To calculate the total number of calories of heat needed, you can use the formula: Q = m * c * ΔT, where Q is the heat energy in calories, m is the mass of the water, c is the specific heat capacity of water (1 calorie/gram °C), and ΔT is the change in temperature. Assuming you have 100 grams of water, the calculation would be: Q = 100g * 1 cal/g°C * 10°C = 1000 calories.
To vaporize 1 gram of boiling water at 100 degrees Celsius, it would require approximately 2260 joules, which is equivalent to about 0.54 calories. This energy is needed to break the intermolecular bonds holding water molecules together, allowing them to escape into the gas phase.
To melt 10 grams of ice at 0 degrees Celsius, it would require 80 calories of heat energy per gram, so a total of 800 calories (80 calories/gram * 10 grams = 800 calories) would be needed.
Approx. 600 - 800 degrees C / 1,100 - 1,500 degrees F
1600
-21 degrees Celsius to 10 degrees Celsius.
To convert 12.5 grams of ice at 0 degrees Celsius to steam at 100 degrees Celsius, you would need to provide heat energy for three main processes: heating the ice from 0 degrees Celsius to 100 degrees Celsius, melting the ice into water at 0 degrees Celsius, and then heating the water from 0 degrees Celsius to steam at 100 degrees Celsius. The total calorie requirement would be determined by the specific heat capacities and heat of fusion and vaporization of water.