The formula of magnesium carbonate is MgCO3. It therefore has one atom each of magnesium and carbon and 3 atoms of oxygen. The gram molecular weight is therefore
24.305 + 12.011 + 3(15.999) = 84.313. This answer to the problem is twice this value, 168.626 grams, if the number "two" is considered to be exact.
The relative molecular mass of magnesium chloride is approximately 60. The molar mass is therefore 60g per mole. Therefore there is 0.42mol of formula units in 2.5 grams.The formula mass of MgCl2 is 24.3 + 2(35.5) = 95.3Amount of MgCl2 = 2.5/95.3 = 0.0262molThere are 0.0262 moles of formula unit in 2.5 grams of magnesium chloride.To get the number (not in moles), multiply the amount in moles by the Avogadro's constant.
The molar mass of magnesium chloride MgCl2 is 95.21 g/mol. To find the mass of 6.80 moles, you would multiply the number of moles by the molar mass: 6.80 moles * 95.21 g/mol = 647.868 g. Therefore, the mass of 6.80 moles of MgCl2 is 647.868 grams.
To calculate the number of moles of magnesium used, you divide the mass of magnesium by its molar mass. The molar mass of magnesium is approximately 24.31 g/mol. For example, if you have 12.15 grams of magnesium, you would divide 12.15 by 24.31 to find that you have 0.5 moles of magnesium.
If you think to the mass of 88,1 moles of magnesium this is 2141,27 g.
By starting with a balanced equation. Mg + 2HCl -> MgCl2 + H2 when they say sufficient magnesium they imply that magnesium is in excess and HCl limits and drives the reaction, or that both are equal in molarity/mass 54.75 g HCl (1 mole HCl/36.458 g)(1 mole MgCl2/2 mole HCl)(95.21 g/1 mole MgCl2) = 71.49 grams magnesium chloride produced -----------------------------------------------------------
To find the number of moles in 444 grams of magnesium chloride, you first need to calculate the molar mass of magnesium chloride. The molar mass of MgCl2 is about 95.21 g/mol. Next, calculate the number of moles by dividing the given mass by the molar mass: 444 g / 95.21 g/mol ≈ 4.66 moles of magnesium chloride.
The relative molecular mass of magnesium chloride is approximately 60. The molar mass is therefore 60g per mole. Therefore there is 0.42mol of formula units in 2.5 grams.The formula mass of MgCl2 is 24.3 + 2(35.5) = 95.3Amount of MgCl2 = 2.5/95.3 = 0.0262molThere are 0.0262 moles of formula unit in 2.5 grams of magnesium chloride.To get the number (not in moles), multiply the amount in moles by the Avogadro's constant.
The molar mass of magnesium chloride MgCl2 is 95.21 g/mol. To find the mass of 6.80 moles, you would multiply the number of moles by the molar mass: 6.80 moles * 95.21 g/mol = 647.868 g. Therefore, the mass of 6.80 moles of MgCl2 is 647.868 grams.
To calculate the number of moles of magnesium used, you divide the mass of magnesium by its molar mass. The molar mass of magnesium is approximately 24.31 g/mol. For example, if you have 12.15 grams of magnesium, you would divide 12.15 by 24.31 to find that you have 0.5 moles of magnesium.
If you think to the mass of 88,1 moles of magnesium this is 2141,27 g.
Molarity= moles/Liters To change grams to moles you divide by the mole weight which is listed on the periodic table. Mol= grams/mol weight The Mole weight of Magnesium Chloride is 59.8 grams/mol Mol=128g/59.8 Mol=2.14 Now, you put the number of moles and Liters into the equation Molarity=2.14 mol/1L Molarity=2.14 So, the molarity is 2.14 M
The molar mass of ammonium chloride (NH4Cl) is approximately 53.49 g/mol. To find the mass of 3 moles, multiply the molar mass by the number of moles: 3 moles x 53.49 g/mol = 160.47 grams of ammonium chloride.
By starting with a balanced equation. Mg + 2HCl -> MgCl2 + H2 when they say sufficient magnesium they imply that magnesium is in excess and HCl limits and drives the reaction, or that both are equal in molarity/mass 54.75 g HCl (1 mole HCl/36.458 g)(1 mole MgCl2/2 mole HCl)(95.21 g/1 mole MgCl2) = 71.49 grams magnesium chloride produced -----------------------------------------------------------
1,11 moles of magnesium have 26,97855 g.
To find the number of moles in 42.5 grams of sodium chloride (NaCl), you first need to calculate the molar mass of NaCl, which is 58.44 g/mol. Then divide the given mass by the molar mass to get the number of moles. In this case, 42.5 grams divided by 58.44 g/mol is approximately 0.727 moles of sodium chloride.
To find the number of chloride atoms in 654.5 grams of calcium chloride, you would first calculate the number of moles of calcium chloride using its molar mass. Then, since each formula unit of calcium chloride contains two chloride ions, you would multiply the number of moles by 2 to find the number of chloride atoms.
To find the molarity of 48.6 grams of magnesium, you first need to determine the number of moles of magnesium in 48.6 grams using the molar mass of magnesium (24.305 g/mol). Then, you divide the moles of magnesium by the volume of the solution in liters to get the molarity.