The numbers corresponded on mine, but if it does not on yours it is number 4 under MOLE-MASS AND MOLE-VOLUME RELATIONSHIPS
Mr Ca3(PO4)2 = 40.1 x 3 +(31.0 +16.0 x 4) x 2
= 310.3 g/mol
0.658 mol = 0.658 x 310.3
=204.2 g
= 204 g (3 significant figures)
28 grams calcium oxide (1 mole CaO/56.08 grams) = 0.50 moles CaO =============
5
The answer is 28,0987.1023 atoms.
10.1 grams
12.8 grams Calcium fluoride (1 mole CaF2/78.08 grams) = 0.163 moles CaF2
5000 grams calcium (1 mole Ca/40.08 grams) = 124.75 moles Calcium
42,5 grams calcium is equivalent to 1,06 moles.
735 g of Ca3(PO4)2 are obtained.
120
Calcium Phosphate itself is basically a general term for a group of different compounds. But many of its forms appear to be a translucent white salt.
120 grams of calcium contain 2,994 moles.
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126 grams calcium (1 mole Ca/40.08 grams) = 3.14 moles of calcium ------------------------------
The formula of anhydrous calcium chloride is CaCl2, and its gram formula mass is 110.99. The gram atomic mass of calcium is 40.08. Therefore, the grams of calcium in 100 grams of calcium chloride is 100(40.08/110.99) or 36.11 grams, to the justified number of significant digits.
6,863 grams of CaO
There are roughly 1000 grams of calcium in the human body. 99% (990 grams) of this calcium is stored in human bone (reservoir for calcium in the body). The remaining 10 grams is circulating in the blood (about 5 grams bound to protein and 5 grams circulating freely).
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