How many grams are there in 0.658 mol of calcium phosphate?

Answer 1

The numbers corresponded on mine, but if it does not on yours it is number 4 under MOLE-MASS AND MOLE-VOLUME RELATIONSHIPS

Mr Ca3(PO4)2 = 40.1 x 3 +(31.0 +16.0 x 4) x 2

= 310.3 g/mol

0.658 mol = 0.658 x 310.3

=204.2 g

= 204 g (3 significant figures)

Answer 2

To find the number of grams in 0.658 mol of calcium phosphate (Ca3(PO4)2), first calculate its molar mass. Ca: 40.08 g/mol, P: 30.97 g/mol, O: 16.00 g/mol. So, the molar mass of Ca3(PO4)2 = 3(40.08) + 2(30.97) + 8(16.00) = 310.18 g/mol. Multiply this molar mass by 0.658 mol to find the grams: 0.658 mol x 310.18 g/mol = approximately 204 grams of calcium phosphate.