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First determine the balanced chemical reaction:
4Al + 3O2 ---> 2Al2O3
Next figure out the number of moles of oxygen you start with by dividing 192 by the molecular weight of oxygen (16 g/mol). Then use the coefficients from the reaction to determine how many moles of Al would need to react with the oxygen to convert all the oxygen and aluminum to aluminum oxide.
192 g * (1 mol O / 16 g O) * (4 moles of Al/6 moles of O) = 8 mol of Al
Finally multiply by the molecular weight of Aluminum to figure out the mass:
8 mol Al * (27 g/mol) = 216 g of Al
What else can I help you with?
If 75 g of oxygen react how many grams of aluminum are required?
The balanced chemical equation for the reaction between aluminum and oxygen is 4Al + 3O2 → 2Al2O3. Using the stoichiometry of the equation, you would need 50 g of aluminum to react with 75 g of oxygen, since the molar ratio between Al and O2 is 4:3.
How many grams of oxygen are needed to react with 6.78 grams of ammonia?
To calculate the number of grams of oxygen needed to react with 6.78 grams of ammonia, we first write out the balanced chemical equation for the reaction between ammonia (NH3) and oxygen (O2) to form nitrogen monoxide (NO) and water (H2O). Then we use the stoichiometry of the equation to find the molar ratio between ammonia and oxygen. Finally, we convert the mass of ammonia to moles and then use the molar ratio to find the mass of oxygen needed.
What is the total mass of water formed when 8 grams of hydrogen reacts completely with 64 grams of ovygen?
The balanced chemical equation for the reaction of hydrogen and oxygen to form water is 2H2 + O2 -> 2H2O. Based on the equation, for every 2 grams of hydrogen, 64 grams of oxygen are needed to form 36 grams of water. Thus, if 8 grams of hydrogen react completely with 64 grams of oxygen, the total mass of water formed would be 36 grams.
In the reaction of aluminum metal and oxygen gas aluminum oxide is formed How many moles of O2 will react with 2.0 moles Al?
In the reaction 4 moles of aluminum will react with 3 moles of oxygen to form 2 moles of aluminum oxide. Since we have 2.0 moles of aluminum, we would need (2.0 mol Al) x (3 mol O2 / 4 mol Al) = 1.5 moles of O2 to react with it.
How many grams of oxygen gas are required to react completely with 14.6 grams of solid sodium to form sodium oxide?
Balanced equation. 4Na + O2 ->2Na2O 14.6 grams Na (1 mole Na/22.99 grams)(1 mole O2/4 mole Na)(32.0 grams/1 mole O2) = 5.08 grams oxygen gas needed --------------------------------------------
How many grams of oxygen are needed to react with 23.9 grams of ammonia?
The balanced equation for the reaction between ammonia (NH3) and oxygen (O2) is 4NH3 + 5O2 → 4NO + 6H2O. To find the grams of oxygen needed to react with 23.9 grams of ammonia, you need to calculate the molar ratio between ammonia and oxygen using the balanced equation. Once you find the molar ratio, you can calculate the grams of oxygen required.
How many grams of oxygen are need to react with 4.6 grams of titanium chloride?
To find the grams of oxygen needed, we first calculate the molar mass of titanium chloride (TiCl4) and oxygen (O2). Then, we use the molar ratio of TiCl4 to O2 from the balanced chemical equation to find the grams of O2 needed.
What is 18.32 grams of aluminum and excess oxygen how many grams of aluminin oxiode are preduced?
Given the balanced chemical equation: 4Al + 3O2 → 2Al2O3, we can see that 4 moles of aluminum react with 3 moles of oxygen to produce 2 moles of aluminum oxide. In this case, 18.32 grams of aluminum is equivalent to 0.684 moles. Using stoichiometry, we find that this would produce 0.456 grams of aluminum oxide.
If 75 g of oxygen react how many grams of aluminum are required?
The balanced chemical equation for the reaction between aluminum and oxygen is 4Al + 3O2 → 2Al2O3. Using the stoichiometry of the equation, you would need 50 g of aluminum to react with 75 g of oxygen, since the molar ratio between Al and O2 is 4:3.
How many grams of oxygen are needed to react with 350 grams of iron to produce 500 grams of fe203?
The balanced chemical equation for the reaction between iron and oxygen to produce Fe2O3 is 4Fe + 3O2 -> 2Fe2O3. From the equation, we see that 3 moles of oxygen react with 4 moles of iron to produce 2 moles of Fe2O3. Therefore, to find the grams of oxygen needed, we need to calculate the molar mass of Fe2O3 and then determine the number of grams needed using the mole ratio from the balanced equation.
How many grams of oxygen are needed to react with 6.78 grams of ammonia?
To calculate the number of grams of oxygen needed to react with 6.78 grams of ammonia, we first write out the balanced chemical equation for the reaction between ammonia (NH3) and oxygen (O2) to form nitrogen monoxide (NO) and water (H2O). Then we use the stoichiometry of the equation to find the molar ratio between ammonia and oxygen. Finally, we convert the mass of ammonia to moles and then use the molar ratio to find the mass of oxygen needed.
How much oxygen in grams will be required to react with 0.5 mole of aluminium?
Three atoms of oxygen are required to react with each two atoms of aluminum to form the most common product of reaction between oxygen and aluminum. Therefore, 0.75 mole of oxygen atoms will be required to react with 0.5 mole of aluminum atoms. The atomic weight of oxygen is 15.999; therefore, the mass will be (0.75)(15.999) = 12 grams of oxygen, to the maximum possibly justified number of significant digits.
If you start with 32 grams of CH4 and react it with O2 to form 88 grams CO2 and 72 grams H2O. How much O2 in grams was consumed?
128 g of oxygen are needed.
How many grams of gas are needed to react with 348.5 grams of oxygen?
To determine the amount of gas needed to react with 348.5 grams of oxygen, you need to know the balanced chemical equation of the reaction. Then, use the stoichiometry of the reaction to calculate the amount of gas required based on the molar ratio between the gas and oxygen in the reaction.
How many grams of aluminum chloride are produced when 54 grams of aluminum react with chlorine gas?
266,86 g aluminium chloride are obtained.
What weight of oxygen will react with 40 gram of ca?
For every 40 grams of calcium (Ca), 32 grams of oxygen (O) will be needed to react. This is based on the chemical formula for calcium oxide (CaO), where one calcium atom reacts with one oxygen atom to form one molecule of CaO.
How many grams of oxygen will react with 2 mole of ethanol?
The balanced chemical equation for the reaction of ethanol with oxygen to form carbon dioxide and water is C2H5OH + 3O2 -> 2CO2 + 3H2O. From this equation, we can see that 3 moles of oxygen are needed to react with 1 mole of ethanol. Therefore, 2 moles of ethanol will require 6 moles of oxygen to react. To find the grams of oxygen, you can multiply the moles of oxygen by its molar mass (32 g/mol).
