An Na(+) ion is just one electron short of a neutral atom. Electrons have a mass of 9.109 X 10^-31 Kilograms. Let us ignore that.
0.187 mol Na(+) (6.022 X 10^23/1mol Na(+)
= 1.13 X 10^22 ions of Na(+)
There are 2.00 mol of KCl, which means there are 2.00 mol x 1 Cl- ion per KCl = 2.00 mol Cl- ions present in 2.00 mol of KCl.
AlCl3 = 3 chloride ions per molecule and so 3 x 1.5 x 6.022 x 1023 2.7099 x 1024
Based on the stoichiometry of NaCl, for every one mole of NaCl there is one mole of Na+ and one mole of Cl-. Therefore, there are 1.5 moles Na+ and 1.5 moles Cl-, totaling 3 moles of ions altogether
Titanium (III) chloride has the formula TiCl3 and therefore contains three chloride ions per formula unit. The number of chloride ions in 0.5 mol is therefore (3/2) X Avogadro's Number or 9 X 1023, to the justified number of significant digits.
Aluminum chloride contains 3 chlorine atoms per molecular unit. Therefore, in 3 moles there are 3 times Avogadro's number of chloride ions = 1.807 X 1024.
2.8 moles Ca3N2 (3 mole Ca 2+/1 mole Ca3N2) = 8.4 moles Ca 2+ =============
In 1.5 mol of SnCl2, there would be 1.5 mol of Sn2+ ions and three times as many Cl- ions due to the 1:2 ratio of SnCl2, so there would be a total of 4.5 mol of ions present.
Na2CO32 * 2 = 4 moles sodium.===========================
When NH4Cl dissolves in water, it dissociates into NH4+ and Cl- ions. Since NH4Cl produces one NH4+ ion and one Cl- ion, for 0.43 mol of NH4Cl, there will be a total of 0.43 mol of NH4+ ions and 0.43 mol of Cl- ions released. Total moles of ions = 0.43 mol NH4+ + 0.43 mol Cl- = 0.86 mol ions The total moles of ions released when 0.43 mol of NH4Cl dissolves in water is 0.86 mol.
There are 2.00 mol of KCl, which means there are 2.00 mol x 1 Cl- ion per KCl = 2.00 mol Cl- ions present in 2.00 mol of KCl.
Each molecule CoCl2 ionises in three single ions (1 Co2+ and 2 Cl- ions), so 0.27 mol CoCl2 gives 3 * 0.27 = 0.81 mole ions (0.27 mole Co2+ and 0.54 mole Cl- ions)
There are 2.75 equivalents of Mg^2+ present in a solution that contains 2.75 mol of Mg^2+. This is because the number of equivalents is equal to the number of moles for ions with a +2 charge.
The number of moles is 8,00944733981.10e23.
When CaCl2 dissociates in water, it forms three ions: one Ca2+ ion and two Cl- ions for each formula unit of CaCl2. Therefore, 0.50 mol of CaCl2 would yield 0.50 mol Ca2+ ions and 1.0 mol Cl- ions in solution, totaling 1.5 moles of ions.
AlCl3 = 3 chloride ions per molecule and so 3 x 1.5 x 6.022 x 1023 2.7099 x 1024
Based on the stoichiometry of NaCl, for every one mole of NaCl there is one mole of Na+ and one mole of Cl-. Therefore, there are 1.5 moles Na+ and 1.5 moles Cl-, totaling 3 moles of ions altogether
0.34 moles Na2O (1 mole O 2-/1 mole Na2O)(6.022 X 1023/1 mole O 2-) 2.1 X 1023 ions of oxygen ================