Each hydrogen atom has 1 protons and the lone oxygen atom has 8 protons (because it is atomic number 8) making for a grand total of 10 protons in each H2O molecule.
There are 3.505 x 10^23 molecules of H2O in 0.583 mol of H2O, because 1 mol of any substance contains 6.022 x 10^23 molecules.
the rule for solving amount of molecules is N(molecules)=6x10^23 x n(amount of mole) therefore there are 6x10^23 molecules in 1 mole of anything or in this case of H20
To calculate the number of molecules in 16.75 grams of H2O, we first need to convert grams to moles (using the molar mass of H2O), and then convert moles to molecules using Avogadro's number. The molar mass of H2O is 18.015 g/mol. After converting, there are approximately 3.52 x 10^23 molecules in 16.75 grams of H2O.
im not really sure but here is what i think it is: 0.943 mole H2Ox 6.02x10^23 molecules H2O= 5.67686^23 molecules H2O sorry if its wrong.
The product of this reaction is 2 water molecules (H2O).
There are 3.34 x 10^22 molecules of H2O in 1.0 g of water.
There is one water molecule in H2O
There are 3.505 x 10^23 molecules of H2O in 0.583 mol of H2O, because 1 mol of any substance contains 6.022 x 10^23 molecules.
0.943 moles H2O (6.022 X 1023/1 mole H2O) = 5.68 X 1023 molecules of water ========================
the rule for solving amount of molecules is N(molecules)=6x10^23 x n(amount of mole) therefore there are 6x10^23 molecules in 1 mole of anything or in this case of H20
Because they are.
There are 1.204 x 10^24 water molecules in two moles of water. This is because one mole of anything contains Avogadro's number of particles, which is 6.022 x 10^23. Thus, two moles of water would have twice that number of molecules.
There are approximately 1.332×10^24 water molecules in the ocean.
During the Krebs cycle, one molecule of water (H2O) is produced for each round of the cycle. At the end of the cycle, a total of two molecules of water per molecule of glucose are generated.
There is 1 O atom in 1 H2O molecule thus there are 12 O atoms in 12 H2O molecules.
45 grams H20 x (1 mole H20/18 grams H2O) x (6.02E23 molecules H20/1 mole H2O) the grams H2O and moles H2O cancel out. When you punch it into your calculator, the answer comes out to: =1.505E24 molecules H2O
Formula mass / Formula weight / Molecular mass / Molecular weight of H2O = (1*2) + 16 = 18g 1 mol of H2O = 18g H2O 1 mol of H2O = 6.023 * 10^23 molecules In 18g H2O there are 6.023 * 10^23 molecules. So, In 1g H2O there are (6.023 * 10^23) / 18 molecules = 3.346 * 10^22 molecules Therefore, In 7.3g H2O there are (3.346 * 10^22) * 7.3 molecules = 2.443 * 10^23 molecules Ans: 2.443 * 10^23 molecules