1 mole NaCl = 58.443g NaCl
234g NaCl x 1mol NaCl/58.443g NaCl = 4.00 moles NaCl
There would be 0.1 moles of NaCl present in 1 liter of a 0.1M solution of sodium chloride. This is based on the definition of molarity which is moles of solute per liter of solution.
Molarity = moles of solute/Liters of solution ( 300 ml = 0.300 Liters ) For our purposes, Moles of solute = Liters of solution * Molarity Moles NaCl = 0.300 Liters * 0.15 M = 0.05 moles NaCl =============
To find the number of moles in 8 grams of NaCl, you need to know the molar mass of NaCl, which is 58.44 g/mol. Divide the given mass (8 grams) by the molar mass to get the number of moles. Therefore, 8 grams of NaCl is equal to 0.14 moles.
The balanced chemical equation for the reaction between HCl and NaOH is: HCl + NaOH -> NaCl + H2O Since the stoichiometry of the reaction is 1:1 for NaCl and HCl, if 1.4 moles of HCl react, then 1.4 moles of NaCl will be formed.
To find the moles of NaCl formed from NaHCO3, we need to consider the stoichiometry of the reaction. The balanced equation is: 2 NaHCO3 -> Na2CO3 + H2O + CO2 Therefore, for every 2 moles of NaHCO3, we get 1 mole of NaCl. Therefore, 3.25 moles of NaHCO3 would produce 1.625 moles of NaCl.
10 moles of sodium chloride have 584,397 g.
The answer is 0,96 moles.
There would be 0.1 moles of NaCl present in 1 liter of a 0.1M solution of sodium chloride. This is based on the definition of molarity which is moles of solute per liter of solution.
Remember the 'moles' equation/ moles = mass(g) / Mr (Relative molecular mass). By algebraic rearrangement mass (g) = moles X Mr . moles(NaCl) = 11 Mr(NaCl) = 23 + 35.5 = 58.5 (From Periodi Table) Hence mass(NaCL) = 11 x 58.5 = 643.5 grams.
The answer is 7,73 moles.
To determine the number of moles of NaCl, you need to know the mass of NaCl you have and the molar mass of NaCl (58.44 g/mol). You can then use the formula moles = mass / molar mass to calculate the number of moles of NaCl.
Of course 6 moles.
There are 1.946 moles of NaCl in 1.946 moles of NaCl. Each mole of NaCl contains Avogadro's number of molecules, which is approximately 6.022 x 10^23.
Molarity = moles of solute/liters of solution ( 50 ml = 0.05 liters ) 2.50 Molar NaCl = moles NaCl/0.05 liters solution = 0.125 moles NaCl ( 7.305 grams NaCl )
The Molecular Weight of NaCl = 58.5 So to make 1L of 4M NaCl solution you need 4*58.5=234g of NaCl So to make 100mL of the above solution you need 23.4 grams of NaCl
Every formula unit of sodium chloride has one sodium atom. Therefore, there are 4.0 moles of sodium ions in 4.0 moles of NaCl.
The answer is 648,68 g.