0
25g / 250ml is 100g per litre. I'll let you know how to finish it. You need to divide by the molecular weight of your compound. I don't think C6H12O16 can actually exist. You may mean glucose, but that is for you to decide. It has been explained how to finish off the math in one step anyway.
What else can I help you with?
How many moles of NaCl are formed from the reaction between 1.4 moles of HCl and 2.8 moles NaOH?
The balanced chemical equation for the reaction between HCl and NaOH is: HCl + NaOH -> NaCl + H2O Since the stoichiometry of the reaction is 1:1 for NaCl and HCl, if 1.4 moles of HCl react, then 1.4 moles of NaCl will be formed.
How would you find the answer to this question How many moles of HCl can be formed when moles of hydrogen gas react with chlorine?
You can determine the moles of HCl formed by using a balanced chemical equation for the reaction between hydrogen gas and chlorine. Calculate the stoichiometric ratio of hydrogen to HCl in the balanced equation to determine the moles of HCl formed from the given moles of hydrogen gas.
What mass of hcl is consumed by the reaction of 2.50 moles of magnesium in equation mg plus hcl equals mgcl2 plus h2?
The balanced chemical equation is: Mg + 2HCl → MgCl2 + H2. Since magnesium reacts with 2 moles of HCl to produce 1 mole of hydrogen, the molar ratio is 2:1. Therefore, with 2.50 moles of magnesium, 5.00 moles of HCl will be consumed. To find the mass of HCl consumed, use the molar mass of HCl (molar mass of HCl = 36.46 g/mol) and the number of moles consumed in the reaction. Thus, the mass of HCl consumed will be 182.3 g.
How many moles of hydrogen chloride can be produced from 0.490 grams of Hydrogen and 50.0 grams of chlorine?
The atomic mass of hydrogen is 1.008 and that for chlorine is 35.45. The moles of hydrogen available are therefore 0.490/1.008 = 0.486 and the moles of chlorine available, 50/35.45, are greater than 1. Each molecule of hydrogen chloride requires one atom each of chlorine and hydrogen. Therefore, with the specified conditions, hydrogen is stoichiometrically limiting, and 0.486 moles of HCl can be made.
How many moles of HCl are consumed in a reaction of 25 mL of 4 M is added to excess CaCO3?
Just multiply 25 mL and 4.0 M but convert 25 mL to liter making it 0.025 L. 0.025 L * 4 M = 0.1 moles
How many moles of HCl and needed to react 2.4 moles of Al?
Al+HCl===> AlCl3+H2 Is the reaction. You need &.2 moles of HCl.
How many moles HCl in 8.3 g HCl?
8.3 grams HCl (1 mole HCl/36.458 grams) = 0.23 moles HCl ------------------------
How many moles of NaCl are formed from the reaction between 1.4 moles of HCl and 2.8 moles NaOH?
The balanced chemical equation for the reaction between HCl and NaOH is: HCl + NaOH -> NaCl + H2O Since the stoichiometry of the reaction is 1:1 for NaCl and HCl, if 1.4 moles of HCl react, then 1.4 moles of NaCl will be formed.
How many moles of solute are in 50 mL of a 12 M HCl solution?
To find the number of moles of solute in the solution, first, calculate the amount of HCl in grams using the formula: moles = molarity x volume (in liters). Then, convert the grams of HCl to moles by dividing by the molar mass of HCl (36.46 g/mol).
How many moles are in 2 grams of HCL?
To find the number of moles in 2 grams of HCl, you need to divide the mass by the molar mass of HCl. The molar mass of HCl is approximately 36.46 g/mol. Therefore, 2 grams of HCl is equal to 2/36.46 = 0.055 moles.
How many moles of HCl are present in 0.250 L of 0.400 M HCl?
Molarity = moles of solute/liters of solution, so... 0.400M HCl (X mols HCl/0.250L ) = 0.100 moles HCl
How many moles of HCl are on 10 grams of substance?
To find the number of moles, you need to divide the given mass (10 grams) by the molar mass of HCl (36.46 g/mol). This will give you approximately 0.274 moles of HCl.
How many moles are in 8.63 mL of HCl?
To determine the number of moles in 8.63 mL of HCl, you need to know the concentration of the HCl solution. Once you have the concentration, you can use the formula: moles = concentration (mol/L) x volume (L) to calculate the moles of HCl present in the given volume.
How many moles of HCl are represented by 1.0x1019 HCl molecules?
To convert from number of molecules to moles, we use Avogadro's number: 1 mole = 6.022x10^23 molecules. Therefore, 1.0x10^19 HCl molecules is equal to 1.66x10^-5 moles of HCl.
How much caustic soda is required to neutralize a 25ml HCl solution at pH 3?
One step at a time.1/103 = 0.001 M HCl, so.....Molarity = moles of solute/Liters of solution ( 25 ml = 0.025 Liters )0.001 M HCl = X moles HCl/0.025 Liters= 2.5 X 10 - 5 moles HCl========================now, balanced eqiationNaOH + HCl --> NaCl + H2O ( all one to one )( now drive reaction towards mass NaOH )2.5 X 10 - 5 moles HCl (1 moles NaOH/1 mole HCl)(39.998 grams/1 mole NaOH)= 10 -4 grams caustic soda needed==========================
How many moles of HCL are in 2.5 L of 0.5 M solution ?
There are 1.25 moles of HCl in 2.5 L of a 0.5 M solution of HCl. This can be calculated by multiplying the volume (2.5 L) by the concentration (0.5 mol/L).
How many moles of HCl are present in 0.70 liters of a 0.33 M HCl solution?
Amount of HCl = 700/1000 x 0.33 = 0.231 moles
