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6.02
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How many oxygen molecules are in 9.1 L of oxygen gas at STP?
at stp 1 mole of a gas contains 22.4 litres. 9.1/22.4= .40625 moles o2. 1 mole of a gas contains 6.022E23 molecules so .40625 moles x 6.022E23 = 2.4464325E23 molecules, but you have to multiply by two due to it being diatomic, so answer x 2 = 4.892875E23 molecules
How many moles of oxygen in 30L of oxygen gas?
At standard temperature and pressure (STP), one mole of a gas is 22.4L. So, in order to determine how many moles of O2 are in 30L, you do the following: multiply 30L O2 x 1mol O2/22.4L O2, which equals 1.34mol O2.
How many moles are present in 10.0 L of nitrogen gas at STP?
Assuming ideal behaviour, 1 mole of any gas occupies 22.4L at STP. So, moles of 10L = 10/22.4 moles = 0.4464 moles
How many moles of nitrogen are contained in 18.65 L at STP?
PV = nRT ⟹ n = PV/RT = 1 * 18.65 / (0.082 * 273.15) = 0.8321 moles.
What volume of oxygen at stpis neededto react with 1.50 moles of c2h4?
To answer this question, it is necessary to have an equation for the reaction. The most common such reaction is complete combustion, which follows the equation: C2H4 + 3 O2 = 2 CO2 + 2 H2O. This equation shows that 3 moles of diatomic oxygen are required to react completely with one mole of C2H4. Therefore, for 1.50 moles of C2H4, 3 X 1.5 = 4.50 moles of oxygen will be required. Oxygen is close to an ideal gas at standard temperature and pressure. Each mole of ideal gas at stp occupies 22.4 liters. Therefore, 4.50 X 22.4 = 101 liters of oxygen, to the justified number of significant digits, will be needed.
How many moles are in 68.5 liters of oxygen gas at STP?
1 mole of any gas occupies 22.4 liters at standard temperature and pressure (STP). Therefore, 68.5 liters of oxygen gas at STP would be 68.5/22.4 = 3.06 moles of oxygen gas.
How many moles of oxygen in 10dm3?
No. of moles = mass/relitive molecular mass in this case = 10/16 = 0.625 so that's 0.625 of a mole and a mole of anything contains 6.022 x 1023 atoms = 3.76 x 1023 atoms in 10g of oxygen.
How many moles of oxygen gas are there in 180 L of oxygen at STP?
If the density of oxygen atSTP is 1,429 g/L the mass of 180 L is 257,22 g.If the mole of oxygen (O2) is 15,999 g the number of moles is 16,077.
Calculate the number of moles in 15 liters of oxygen at STP?
At STP (Standard Temperature and Pressure), 1 mole of any gas occupies 22.4 liters. Therefore, 15 liters of oxygen at STP would be equivalent to 15/22.4 = 0.67 moles.
How many moles of methane are presentin 5.6L of the gas at stp?
0.25 moles
How many moles are contained in 16.8 L of Xe gas at STP?
16,8 L of Xe gas at STP is equivalent to 0,754 moles.
How many moles are present in 8.4 liters of nitrous oxide at STP?
8,4 liters of nitrous oxide at STP contain 2,65 moles.
What is the number of moles of gas in 30 L of oxygen at STP?
Ideal gas law.PV = nRT(1.00 atmosphere)(30 L) = n(0.08206 L*atm/mol*K)(298.15 K)n(moles O2) = 30/24.466= 1.2 moles oxygen gas================
What is the volume of 2 mol of oxygen?
The molar volume of a gas at standard temperature and pressure (STP) is 22.4 L/mol. Therefore, the volume of 2 moles of oxygen gas at STP would be 2 moles * 22.4 L/mol = 44.8 L.
What volume occupied by 1.50 moles of CH4 at STP is?
The amount of oxygen is 0,067 moles.
How many moles of argon are found in a 5L sample of argon at STP?
At STP, 1 mole of any gas occupies 22.4 L. Therefore, in a 5L sample of argon at STP, there would be 5/22.4 moles of argon, which is approximately 0.223 moles.
How many moles of nitrogen does it take to fill a 60.0 liter space of stp?
The answer is 2,68 moles.
