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How many moles of sulphur in 1.81 X 1024 atoms of sulphur ? The answer is 3. The fact that we are talking about sulphur is immaterial. A mole is just another name for a gram molecular weight. The number of atoms in a gmw (mole) is given by Avogadro's Number, which is 6 X 1023 no matter what the element.

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Q: How many moles of sulfur are found in 1.81 X 10 exp24 atoms of sulfur?
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How many moles of sulfur are in 3.2x1022 atoms of sulfur?

3,2x10e22 atoms of sulfur is equivalent to 0,053 moles.


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To find the number of sulfur atoms in a given mass of sulfur, you can use the following steps: Determine the number of moles of sulfur using the formula: moles = mass molar mass moles= molar mass mass ​ Given that the molar mass of sulfur ( S S) is 32.06 g/mol and the mass ( m m) is 1.56 g: moles = 1.56   g 32.06   g/mol moles= 32.06g/mol 1.56g ​ Once you have the moles of sulfur, you can use Avogadro's number (6.022 x 1 0 23 10 23 mol − 1 −1 ) to find the number of atoms: number of atoms = moles × Avogadro’s number number of atoms=moles×Avogadro’s number Let's calculate it: moles = 1.56   g 32.06   g/mol ≈ 0.0488   mol moles= 32.06g/mol 1.56g ​ ≈0.0488mol number of atoms = 0.0488   mol × ( 6.022 × 1 0 23   mol − 1 ) number of atoms=0.0488mol×(6.022×10 23 mol −1 ) number of atoms ≈ 0.0488 × 6.022 × 1 0 23 number of atoms≈0.0488×6.022×10 23 number of atoms ≈ 3.0 × 1 0 22 number of atoms≈3.0×10 22 Therefore, there are approximately 3.0 × 1 0 22 3.0×10 22 sulfur atoms in 1.56 g of sulfur.


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