4
Fluorine is a halogen. All halogens have 7 valence electrons. There are thus 7 valence electrons for Fluorine, 2 in the 2s orbital, and 5 in the 2p orbitals.
Hydrogen has 1 valence electron, phosphorus has 5 valence electrons, and oxygen has 6 valence electrons. So, if you totaled all of the valence electrons in the ion HPO42- you'd get 1 + 5 + 6 X 4 + 2 = 32. However, you should realize that the term "valence electron" really only applies to individual atoms, not compounds. The only electrons one would concern themselves with in the HPO42- ion are the 2 that make it an ion.
Nitrogen has 2s^3 2p^3 valence electrons so the answer would be 3
If it's a -1, then that would be adding an electron.NH = 9 valence electrons (n=5 h=1(4))4the -1 would just add an electron.
4
A chlorine atom has 7 valence electrons.
The are none.
6
It depends on what group or family the element is in. For example, Potassium is in the first group of family so it only has 1 valence electron. However, since nitrogen is in the 15 group of family, it does not have 15 valence electrons. For double digit families, you just take the second digit, and that is the number of valence electrons. Therefore, Nitrogen would have 5 valence electrons.
Helium has 2 valence electrons, and it's the only noble gas that doesn't have 8 valence electrons.
They are the electrons in the outermost shell, and are the ones involved in most chemical reactions.
3
There are 6 valence electrons in tellurium On the 5th energy level, it's valence shell
3 valence electrons. As the atomic number of boron is 5, it would have 2 electrons in the first shell and 3 valence electrons in the second shell.
Valence electrons are the total amount of electrons on the outermost shell of an atom. Meaning if the last shell has two, the valence electrons are two. But a complete valence shell would hold eight.
A neutral atom of oxygen would have 6 valence electrons.