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delta H=[2(-791.4kJ)]-o.oo-o.oo

delta H=-1582.8 kJ/mol

(6.44g S x 1mole S x 2 moles SO3) / (32.06g S x 1mole S)=0.200moles SO3

(0.200mole x -791.4) / (2 moles) = -79.14

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Q: How much heat will be released when 6.44 grams of sulfur reacts with excess oxygen?
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