The specific heat of water is ~ 1calorie per gram per degC
to drop 1 g of water 40 C requires the loss of 40 calories of heat or -167.36 Joules
1 J = .239 cal
decrease due to expansion
Density is a characteristic of a given material. Water, for example, has a certain density (which is somewhat dependent upon temperature but let's say that the temperature is constant). It does not matter how much water you have, it will all have the same density. One teaspoon has much less mass, but the same density as an entire ocean.
Heat capacity is the amount of heat energy required to raise the temperature of a unit mass of a material one degree.
An increase in temperature usually causes an increase in volume. Since the mass doesn't change, density decreases. tt
yes
Temperature will have no effect on mass, however it generally causes the volume to expand (I say generally, because there is a small range in where an increase in temperature cause contraction). Since volume grows and mass stays the same, then density will decrease.
The mass remain unchanged.
Removing the salt from the water would increase the temperature required for it to freeze, and also lower the temperature it takes to boil.Meaning it would freeze more easily.
For a given volume and pressure, the mass of the air contained in that volume (density) will decrease as the temperature increases.
Density is mass per unit volume of a substance. The Mass and volume of water is in the ratio of 1:1 .There fore the density of water is 1. With rise and decrease of temperature the volume increases or decreases to change the water density.
You need to add all of the following:* The heat required to heat ice from -5 to 0 degrees. Multiply the mass times the temperature difference times the specific heat of ice. * The heat required to melt ice. Multiply the mass by the heat of fusion. * The heat required to raiste the temperature of water from 0 to 20 degrees. Multiply the mass times the temperature difference times the specific heat of water.
heat energy required to raise the temperature of ice by 29 celsius =specific heat capacity of ice * temperature change *mass of ice + to change 1kg of ice at 0 celsius to water at 0 celsius =specific latent of fusion of ice*mass of water + heat energy required to raise the temperature of water by 106 celsius =specific heat capacity of water * temperature change *mass of ice + to change 1kg of water at 106 celsius to steam at 106 celsius =specific latent of fusion of ice*mass of steam
You need o know the initial temperature of water:Heat = specific heat x difference of temperature x mass of water
The temperature and pressure rise.
decrease due to expansion
No, it does not violate the law of conservation of mass. The reason for this is that the decrease in mass of the compound can be found in the mass of the water that was lost upon heating. Thus, total mass remains constant.
Mass of any chemical, in Chemistry, is always constant, no matter how much you change the conditions.