0
Dissolve 74.55g of KCL in some water then volume it up to 1 liter.
Wiki User
∙ 11y ago
Wiki User
∙ 8y agoDissolve 53 g sodium carbonate in 1 kg of water.
Wiki User
∙ 7y agoDissolve 95,211 g anhydrous chloride in 1kg distilled water.
Wiki User
∙ 11y agoFor 1 N CaCl2 ≡ 55.5 gms in 1 lit.
Wiki User
∙ 11y agohnnzlc .z
Add your answer:
Earn +20 pts
How many grams of KCl are required to prepare 2.25L of a 0.75m KCl solution?
Molarity = moles of solute/Liters of solution 0.75 M KCl = moles KCl/2.25 Liters = 1.6875 moles KCl (74.55 grams/1 mole KCl) = 126 grams of KCl needed
What is the cell constant of 0.1 and 0.01 M KCl solution?
1 meter
The molarity of a solution of 5.0 g of KCl in 100 mL of solution is?
0.67 M
How you prepare 0.02 M KCl solution?
I'll straightly go to the equation. KCL molar mass is 74.5513 g/mol. To prepare 0.02 M KCL solution, *0.02 M is also known as 0.02 mol/litre. 74.5513 g/mol x 0.02 mol/litre x 1 litre = 1.4910 g *note that in the equation we can cancel the mol and litre leave out the gram alone. So we need only 1.4910 g of KCL in 1 litre. You can change the volume, depend on your convenience but must in litre unit.
How many grams of KCl would you need to make 250 ml of a 5 M solution?
MW 74.5, 1M solution requires 74.5g in 1L, 5M solution requires 74.5x5 = 372.5g in 1 L. You would need 93.1g KCL to make 250mL 5M solution
How will you prepare 3 liters of 2.5 M solution of KCl solution in water?
Dissolve 566.25g of KCl in 3L.
How many grams of KCl are needed to prepare 125 mL of a 0.720 M KCl solution?
The answer is 6,71 g dried KCl.
How you prepare 3 M KCl solution?
Weigh 22.35 grams of KCl and Dissolve in 100 mL of Distilled Water
How many grams of KCl are required to prepare 2.25L of a 0.75m KCl solution?
Molarity = moles of solute/Liters of solution 0.75 M KCl = moles KCl/2.25 Liters = 1.6875 moles KCl (74.55 grams/1 mole KCl) = 126 grams of KCl needed
What volume of 0.060 M KCl solution contains 2.39g of KCl?
MW KCl = 74.6 g/mol2.39 gKCl * (1 mol KCL/74.6 g KCl)*(1 L solution/0.06 mol KCL) = 0.534 L
How much 75.66MKCL is required toprepare 1L of solution?
I did not know that you could get a concentration of 75.66 M KCl, but; Molarity = moles of solute/Liters of solution 75.66 M KCl = moles KCl/1 liter = 75.66 moles of KCl 75.66 moles KCl (74.55 grams/1 mole KCl) = 5640 grams KCl that is about 13 pounds of KCl in 1 liter of solution. This is why I think there is something really wrong with this problem!
What mass of KCl is required to prepare 383.00 mL of 0.500 M solution?
I'll go straight to the equation, to prepare 0.5 M of KCl in 383 ml, simply calculate it this way, *Molar mass of KCl is 74.5513 g/mol *0.5 M is also known as 0.5 mol/Litre 74.5513 g/mol x 0.5 mol/litre x 0.383 Litre = 14.2766 g So, you need 14.2766 g of KCl to prepare 0.5 M in 383 ml solution.
What is the cell constant of 0.1 and 0.01 M KCl solution?
1 meter
How many moles of KCl are contained in 0.635L of 2.2M KCl?
moles KCl = ( M solution ) ( V solution in L )moles KCl = ( 2.2 mol KCl / L solution ) ( 0.635 L of solution )moles KCl = 1.397 moles KCl
How many moles of KCl are needed to prepare 1.00 L of a 1.0M KCl solution?
M= moles in solution/liters so plug in what you know 3.0M of KCl solution = moles in solution/ 2.0L multiply both sides by 2.0L moles solute = 1.5 moles KCl so you need 1.5 moles KCl to prepare the solution
What is the molarity of a solution made by dissolving 4.88 g of KCl in 423 mL of solution?
Need mole KCl first. 4.88 grams KCl (1 mole KCl/74.55 grams) = 0.06546 moles KCl =======================now, Molarity = moles of solute/Liters of solution ( 423 ml = 0.423 Liters ) Molarity = 0.06546 moles KCl/0.423 Liters = 0.155 M KCl ------------------
How many moles of KCl are contained in 1.7L of a 0.83M KCl solution?
moles KCL = ( M solution ) ( L of solution )moles KCl = ( 0.83 mol KCl / L ) ( 1.7 L ) = 1.41 moles KCl
