You are doubling the amount of D, so 8*2 = 16 grams of D required.
Si + 2Cl2 --> SiCl4 24.4 grams silicon (1 mole Si/28.09 grams)(2 mole Cl2/1 mole Si)(70.9 grams/1 mole Cl2) = 123 grams chlorine needed =====================
There are 32 grams of sulfur in a mole of that element. There are also 32 grams of oxygen in one mole of oxygen as it is found in its natural state (O2).
Fe3Cl
How many MOLES of sodium nitrate are present in 2.85 grams of this compound ?
Mixture
This is just simple maths. If you need 2 grams of X for every 4 grams of Y, you need to multiply this up to the scale you are given 2x = 4y 4x = 8y 6x = 12y So you would need 6 grams of element X to make the same compound.
banana element
Multiply the mass of the compound by the conversion factor based on the percent composition of the element in the compound
8.85
This depends on the compound.
The percentage of oxygen is 54,84 %.
It depends on the substance. If you have for example, 12 grams of Carbon-12. Then you have 1 mole of carbon 12 which is 6.02 * 1023 molecules of the element, which is equal to 12 grams. One mole of a compound or element is equal to that element's atomic mass in grams.
Multiply the number of moles by the molecular weight of the compound (or atomic weight for an element) to find the mass in grams.
The mass in grams of 1 mole of the compound (apex)
1) Get the chemical formula to determine the number of each type of atom present in the compound. 2) Multiply the atomic weight (get it from the periodic table) of each element by the number of atoms of that element present your specific compound 3) Do the Sum in unit grams/mole NaCl (1x23 grams/mole Na) + (1x 35.5 grams/mole Cl) = 58.5 grams/mole NaCl
A gravimetric factor converts grams of a compound into grams of a single element. For example, we'll find the gravimetric factor of Cl in AgCl. Use the atomic mass of Ag(107.868) and the atomic mass of Cl(35.453) and add them together to get 143.3. Then divide 35.453 by 143.3 to get .2474. .2474 is the gravimetric factor of Cl in AgCl.
number of moles = mass of the material/molar mass