Balmer series just represents the visible radiations region and it is present in the
spectra of every element.
It is just the case that we study only hydrogen atom.
There is 1 hydrogen atom and 1 chlorine atom in Hydrogen Chloride.
No, C3H9N does not have hydrogen bonds. Hydrogen bonds occur when hydrogen is bonded to an electronegative atom like oxygen, nitrogen, or fluorine, and in C3H9N, there are only carbon, hydrogen, and nitrogen atoms present.
H2S contains two elements: hydrogen and sulfur.
There is one atom of hydrogen in a hydrogen molecule.
There is one atom in Hydrogen and one atom in Chlorine. All elements are composed of only one atom.
The wavelength of the hydrogen atom in the 2nd line of the Balmer series is approximately 486 nm. This corresponds to the transition of an electron from the third energy level to the second energy level in the hydrogen atom.
The electron transition from n=5 to n=1 in a hydrogen atom corresponds to the Balmer series, specifically the Balmer-alpha line which is in the visible part of the spectrum.
The ratio of the wavelengths of the last line in the Balmer series to the last line in the Lyman series is 1:5. The Balmer series is associated with transitions to the n=2 energy level, while the Lyman series is associated with transitions to the n=1 energy level in the hydrogen atom.
The Lyman series consists of transitions to the n=1 state, the Balmer series to the n=2 state, and the Paschen series to the n=3 state in the hydrogen atom. Each series represents a specific range of wavelengths or frequencies of electromagnetic radiation emitted by hydrogen when electrons transition between these energy levels.
The line spectrum of the hydrogen atom consists of discrete lines at specific wavelengths corresponding to different electron transitions within the atom. These lines are a result of the energy differences between electron orbitals in the atom. Each line represents a specific electron transition, such as the Lyman, Balmer, and Paschen series.
The formula parallel to Rydberg's formula used in Bohr's theory of the emission spectrum of the hydrogen atom is the Balmer Series. See related link for more information.
The particular colors emitted by an element reflect the exact amounts of energy that electrons orbiting the hydrogen nucleus give off when they drop from higher energy positions further from the nucleus to lower energy positions closer to the nucleus. Since hydrogen is so small and has so few orbitals, it has only four colors that it emits on the Balmer Series. Elements with high atomic numbers have many more orbitals and thus many more colors.
This atom is hydrogen.
There is 1 hydrogen atom and 1 chlorine atom in Hydrogen Chloride.
That led to know about the size of the atom and the reason of getting five different series of spectral lines in case of hydrogen such Lymann, Balmer, Pashcen, Bracket and Pfund.
The isotope hydrogen-1 don't contain neutrons.
The Bohr model of the atom was able to explain the Balmer series by proposing that electrons orbit the nucleus in quantized, discrete energy levels. The transition of electrons between these levels corresponds to the emission of light at specific wavelengths, which gives rise to the spectral lines observed in the Balmer series.