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The charge on calcium in CaBr2 is +2. This is because calcium is a group 2 element and typically forms 2+ cations in compounds.
The formula for the ionic compound formed by calcium and bromine is CaBr2. Calcium, a group 2 element, has a 2+ charge while bromine, a group 17 element, has a 1- charge. To balance the charges, two bromine ions combine with one calcium ion to form CaBr2.
The acid-base reaction of hydrobromic acid, HBr, and calcium hydroxide, Ca(OH)2, forms a salt and water, namely the bromine salt of calcium, CaBr2, and water, H2O. It looks like this: HBr + Ca(OH)2 => CaBr2 + H2O All we need to do to balance the equation is make a couple of small changes: 2HBr + Ca(OH)2 => CaBr2 + 2H2O
The empirical formula would be CaBr2 since it contains a ratio of 1 calcium to 2 bromine atoms.
Sulfur is not conductive in its pure form. However, when combined with certain materials to form compounds like sulfuric acid or iron sulfide, it can exhibit conductive properties.
To find the number of moles of CaBr2 in 5.0 grams, you first need to calculate the molar mass of CaBr2. The molar mass of CaBr2 is 200.8 g/mol. Divide the given mass by the molar mass to find the number of moles: 5.0 g / 200.8 g/mol = 0.025 moles of CaBr2. Since there is one mole of CaBr2 for every two moles of CaBr, you have half of that amount in moles of CaBr: 0.025 moles / 2 = 0.0125 moles of CaBr.
The chemical formula for calcium bromide is CaBr2.
Well, darling, if you want to know how many moles of CaBr2 are in 5.0 grams, you just need to divide the mass by the molar mass of CaBr2. The molar mass of CaBr2 is approximately 199.89 g/mol, so 5.0 grams of CaBr2 is roughly 0.025 moles. Hope that helps, sugar!
To find the number of grams of CaBr2 in 0.31 moles, you first calculate the molar mass of CaBr2, which is approximately 199.89 g/mol. Then, you can multiply the number of moles (0.31 moles) by the molar mass to find the grams: 0.31 moles x 199.89 g/mol = 61.97 grams of CaBr2.
Ca + Br2 = CaBr2 doesn't need to be balanced.
A solution of CaBr2 is neutral. When CaBr2 dissolves in water, it dissociates into calcium ions (Ca2+) and bromide ions (Br-), which do not significantly affect the pH of the solution.
The answer to this question is Calcium (Ca) Br2 (-ide) Bromide. Put them together, you get Calcium Bromide.
1st you must find the molar mass of CaBr2. Ca 40.08g * (number of moles in the compound) 1 Br 79.90g * 2 This give you the amount (g) in 1 mole of CaBr2. Multiply by 14 and you get the answer.
In an aqueous solution of CaBr2, the solute particles are Ca2+ cations and Br- anions. When dissolved in water, CaBr2 dissociates into these ions, which are responsible for conducting electricity and other properties of the solution.
In the reaction Ca + Br2 → CaBr2, calcium acts as the reducing agent because it undergoes oxidation by losing electrons to bromine. This results in the formation of calcium bromide (CaBr2).
CaBr2 is calcium bromide, an alkaline halide salt.Na2CO3 is sodium carbonate, which is very similar to baking soda.
CaBr2