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Potassium chloride can be a solute if is dissolved in water.
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Is KCl a solute or a solvent?
Potassium chloride, KCl, is a salt; it dissolves in water and would be considered a solute when it does so.
How many grams of KCl are required to prepare 2.25L of a 0.75m KCl solution?
Molarity = moles of solute/Liters of solution 0.75 M KCl = moles KCl/2.25 Liters = 1.6875 moles KCl (74.55 grams/1 mole KCl) = 126 grams of KCl needed
Which statement describes KCl 1a solute in a homogenous mixture. 2a solute in a heterogenous mixture. Note please provide relevant details. Thanks.?
it is the component of the solution in smaller amount.. "S"- lovers...
Indicate the principal type of solute-sovent interaction and rank the solutions from weakest to strongest interaction KCl in water and Ch2Cl2 in benzene C6H6 and CH3OH in H2O?
a. KCl in water b. CH3OH in H2O c. CH2Cl2 in benzene
How many grams of KCl are needed to make 100 ml of a 3.5M solution?
In a 3.4 M solution, there are 3.4 moles per liter. If you want to make 3 liters of solution, you'll need 3 liter * 3.4 moles/liter = 10.2 moles The molar mass of KCl is 39.098 g/mole K + 35.453 g/mole Cl = 74.551 g/mole KCl To get the number of grams, multiply the number of moles by the molar mass: 10.2 moles * 74.551 g/mole KCl = 760.4202 g = 0.760 kg
Is KCl a solute or a solvent?
Potassium chloride, KCl, is a salt; it dissolves in water and would be considered a solute when it does so.
How many grams of KCl are required to prepare 2.25L of a 0.75m KCl solution?
Molarity = moles of solute/Liters of solution 0.75 M KCl = moles KCl/2.25 Liters = 1.6875 moles KCl (74.55 grams/1 mole KCl) = 126 grams of KCl needed
How many moles of KCl are contained in 121mL of a 1.68M KCl solution?
Molarity is moles of solute per L of solution.moles KCl = ( 1.68 M ) ( 0.121 L ) = ( 1.68 mol/L ) ( 0.121 L )moles KCl = 0.203 moles KCl
How many moles of KCL are present in 50.0ml of a 0.552 M solution?
Molarity = moles of solute/Liters of solution ( 50.0 ml = 0.05 Liters ) 0.552 M KCl = moles/.0.05 liters = 0.0276 moles of KCl
How much 75.66MKCL is required toprepare 1L of solution?
I did not know that you could get a concentration of 75.66 M KCl, but; Molarity = moles of solute/Liters of solution 75.66 M KCl = moles KCl/1 liter = 75.66 moles of KCl 75.66 moles KCl (74.55 grams/1 mole KCl) = 5640 grams KCl that is about 13 pounds of KCl in 1 liter of solution. This is why I think there is something really wrong with this problem!
What is the molarity of a solution made by dissolving 4.88 g of KCl in 423 mL of solution?
Need mole KCl first. 4.88 grams KCl (1 mole KCl/74.55 grams) = 0.06546 moles KCl =======================now, Molarity = moles of solute/Liters of solution ( 423 ml = 0.423 Liters ) Molarity = 0.06546 moles KCl/0.423 Liters = 0.155 M KCl ------------------
How many moles of KCl are needed to prepare 1.00 L of a 1.0M KCl solution?
M= moles in solution/liters so plug in what you know 3.0M of KCl solution = moles in solution/ 2.0L multiply both sides by 2.0L moles solute = 1.5 moles KCl so you need 1.5 moles KCl to prepare the solution
What is the molarity of a solution that contains .202 mol KCI in 7.98 L of solution?
Molarity = moles of solute/Liters of solution Molarity = 0.202 moles KCl/7.98 Liters = 0.253 M KCl solution ================
Which statement describes KCl 1a solute in a homogenous mixture. 2a solute in a heterogenous mixture. Note please provide relevant details. Thanks.?
it is the component of the solution in smaller amount.. "S"- lovers...
Indicate the principal type of solute-sovent interaction and rank the solutions from weakest to strongest interaction KCl in water and Ch2Cl2 in benzene C6H6 and CH3OH in H2O?
a. KCl in water b. CH3OH in H2O c. CH2Cl2 in benzene
How many grams of KCl are needed to make 100 ml of a 3.5M solution?
In a 3.4 M solution, there are 3.4 moles per liter. If you want to make 3 liters of solution, you'll need 3 liter * 3.4 moles/liter = 10.2 moles The molar mass of KCl is 39.098 g/mole K + 35.453 g/mole Cl = 74.551 g/mole KCl To get the number of grams, multiply the number of moles by the molar mass: 10.2 moles * 74.551 g/mole KCl = 760.4202 g = 0.760 kg
What is the mass percent of a solution that is prepared by dissolving 4.0 g of KCl in 50.0 g of H2O?
Mass percent is the ratio of the mass of solute to the total mass of solution expressed as a percent Here we have 4.0 g solute and total mass of solution of 4.0 g + 50.0 g = 54.0 g. So, the mass percent of KCl = 4.0 g/54.0g (x100) = 7.41% (3 sig figs)
