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Is KCl a solute or a solvent?
Potassium chloride does form an aqueous solution when dissolved in water.
Which statement describes KCl 1a solute in a homogenous mixture. 2a solute in a heterogenous mixture. Note please provide relevant details. Thanks.?
In a homogeneous mixture, KCl is dissolved uniformly in the solvent, creating a single-phase solution where the KCl particles are evenly distributed and not visible to the naked eye. In a heterogeneous mixture, KCl exists as visible particles suspended in the solvent without fully dissolving, creating a two-phase system where the KCl particles can settle out over time due to gravity.
5 grams of KCl is dissolved in 100 grams of water Which component is the solvent?
The component water is the solvent in this case.
How many grams of KCl are required to prepare 2.25L of a 0.75m KCl solution?
To calculate the grams of KCl needed, first determine the molar mass of KCl (74.55 g/mol). Then use the formula: grams = molarity x volume (L) x molar mass. Plugging in the values, you get: grams = 0.75 mol/L x 2.25 L x 74.55 g/mol = 126.60 grams of KCl.
How many grams of KCl are needed to make 100 ml of a 3.5M solution?
In a 3.4 M solution, there are 3.4 moles per liter. If you want to make 3 liters of solution, you'll need 3 liter * 3.4 moles/liter = 10.2 moles The molar mass of KCl is 39.098 g/mole K + 35.453 g/mole Cl = 74.551 g/mole KCl To get the number of grams, multiply the number of moles by the molar mass: 10.2 moles * 74.551 g/mole KCl = 760.4202 g = 0.760 kg
Is KCl a solute or a solvent?
Potassium chloride does form an aqueous solution when dissolved in water.
How do you calculate the molaity of KCl?
Molality (m) is calculated by dividing the moles of solute by the mass in kilograms of the solvent. For potassium chloride (KCl), you would first calculate the moles of KCl present, then divide by the mass of the solvent (usually water) in kilograms. The formula is m = moles of solute / kg of solvent.
How many moles of KCl are contained in 121mL of a 1.68M KCl solution?
Molarity is moles of solute per L of solution.moles KCl = ( 1.68 M ) ( 0.121 L ) = ( 1.68 mol/L ) ( 0.121 L )moles KCl = 0.203 moles KCl
How much 75.66MKCL is required toprepare 1L of solution?
I did not know that you could get a concentration of 75.66 M KCl, but; Molarity = moles of solute/Liters of solution 75.66 M KCl = moles KCl/1 liter = 75.66 moles of KCl 75.66 moles KCl (74.55 grams/1 mole KCl) = 5640 grams KCl that is about 13 pounds of KCl in 1 liter of solution. This is why I think there is something really wrong with this problem!
What is the molarity of a solution that contains .202 mol KCI in 7.98 L of solution?
Molarity = moles of solute/Liters of solution Molarity = 0.202 moles KCl/7.98 Liters = 0.253 M KCl solution ================
How many moles of KCl are needed to prepare 1.00 L of a 1.0M KCl solution?
M= moles in solution/liters so plug in what you know 3.0M of KCl solution = moles in solution/ 2.0L multiply both sides by 2.0L moles solute = 1.5 moles KCl so you need 1.5 moles KCl to prepare the solution
Which statement describes KCl 1a solute in a homogenous mixture. 2a solute in a heterogenous mixture. Note please provide relevant details. Thanks.?
In a homogeneous mixture, KCl is dissolved uniformly in the solvent, creating a single-phase solution where the KCl particles are evenly distributed and not visible to the naked eye. In a heterogeneous mixture, KCl exists as visible particles suspended in the solvent without fully dissolving, creating a two-phase system where the KCl particles can settle out over time due to gravity.
5 grams of KCl is dissolved in 100 grams of water Which component is the solvent?
The component water is the solvent in this case.
What volume of 0.060 M KCl solution contains 2.39g of KCl?
To find the volume of the solution, first calculate the number of moles of KCl in 2.39g using its molar mass (74.55 g/mol). Then, use the molarity equation (Molarity = moles of solute / volume of solution in liters) to find the volume of the solution.
What is the molarity of a solution made by dissolving 4.88 g of KCl in 423 mL of solution?
Need mole KCl first. 4.88 grams KCl (1 mole KCl/74.55 grams) = 0.06546 moles KCl =======================now, Molarity = moles of solute/Liters of solution ( 423 ml = 0.423 Liters ) Molarity = 0.06546 moles KCl/0.423 Liters = 0.155 M KCl ------------------
How many grams of KCl are required to prepare 2.25L of a 0.75m KCl solution?
To calculate the grams of KCl needed, first determine the molar mass of KCl (74.55 g/mol). Then use the formula: grams = molarity x volume (L) x molar mass. Plugging in the values, you get: grams = 0.75 mol/L x 2.25 L x 74.55 g/mol = 126.60 grams of KCl.
What is the molarity of a solution that contains 345 moles KCL in 8.6 L solution?
The molarity of the solution is 40.1 M. This is calculated by dividing the moles of solute (345 mol KCl) by the volume of solution in liters (8.6 L).
