Yea your gonna die
Just multiply 25 mL and 4.0 M but convert 25 mL to liter making it 0.025 L. 0.025 L * 4 M = 0.1 moles
*first you set the equation: -(10mL of HCl)(1 mol of HCl)/(22.4 mL of HCl)= .446 mol of HCl *you divide by the volume of HCl which is 22.4 at STP. *Then you will divide that .446 mol of HCl with the mol of Zn, which is 1: -(.446 mol of HCl)( I mol of Zn)/(1 mol of HCl)= .446 mol Zn
At 25 deg C, Heat= -176000 J approx
25g / 250ml is 100g per litre. I'll let you know how to finish it. You need to divide by the molecular weight of your compound. I don't think C6H12O16 can actually exist. You may mean glucose, but that is for you to decide. It has been explained how to finish off the math in one step anyway.
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V = volume, M = molarity V1M1=V2M2 (25 mL)(0.0010 M) = (x)(0.010 M) x = (25 mL)(0.0010 M)/(0.010 M) x = 2.5 mL To make a 25 mL 0.0010 M HCl solution with 0.010 M HCl, you would measure out 2.5 mL of the 0.010 M HCl in a 25 mL graduated cylinder (or laboratory equipment of your choice) and then add 22.5 mL of distilled water.
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You can,but you'll die. :(
Just multiply 25 mL and 4.0 M but convert 25 mL to liter making it 0.025 L. 0.025 L * 4 M = 0.1 moles
To prepare a 10 ml of a 25 M HCl solution, you would need to dilute the 1 M HCl solution by a factor of 25. You will need 0.25 ml of the 1 M HCl solution and 9.75 ml of solvent (usually water) to make a total volume of 10 ml for the 25 M HCl solution.
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Use the formula M1V1 = M2 V2 25 M X V1 = [4.1 x 10 -2 ]M x 1.5 L V1 = [4.1 x10-2 x 1.5] / 25 V1 = 0.00246 L = 2.5 mL Take 2.5 mL of 25 M HCl and put it in a analytical measuring flask and complete the rest volume with distilled water (until the total volume is 1500 mL).
you cant solve that without the concentration of the HCl or the mass if you have either of these use: To find the moles with mass of HCl you have use n= m/mm , m=mass of HCl and mm = the molar mass so the elements mass combined from periodic table to find the moles with the volume = 0.06 (in litres must be!) and concentration use n = cv
Making 25 mm Borate HCL buffer with a pH of 8.8 will require careful calculation and measurement. The pH can be easily adjusted after formulation. Temperature can impact the pH.
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