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How do you make 25 ml of a 0.0010 M HCl starting with 0.010 M HCl?

V = volume, M = molarity V1M1=V2M2 (25 mL)(0.0010 M) = (x)(0.010 M) x = (25 mL)(0.0010 M)/(0.010 M) x = 2.5 mL To make a 25 mL 0.0010 M HCl solution with 0.010 M HCl, you would measure out 2.5 mL of the 0.010 M HCl in a 25 mL graduated cylinder (or laboratory equipment of your choice) and then add 22.5 mL of distilled water.


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You can,but you'll die. :(


How many moles of HCl are consumed in a reaction of 25 mL of 4 M is added to excess CaCO3?

Just multiply 25 mL and 4.0 M but convert 25 mL to liter making it 0.025 L. 0.025 L * 4 M = 0.1 moles


How would one prepare 10 ml of a 25 M HCI solution if 1 M HCI was available?

To prepare a 10 ml of a 25 M HCl solution, you would need to dilute the 1 M HCl solution by a factor of 25. You will need 0.25 ml of the 1 M HCl solution and 9.75 ml of solvent (usually water) to make a total volume of 10 ml for the 25 M HCl solution.


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What volume of 25 M HCl must be diluted to prepare 1.5 L of 4.1x10-2 M HCl?

Use the formula M1V1 = M2 V2 25 M X V1 = [4.1 x 10 -2 ]M x 1.5 L V1 = [4.1 x10-2 x 1.5] / 25 V1 = 0.00246 L = 2.5 mL Take 2.5 mL of 25 M HCl and put it in a analytical measuring flask and complete the rest volume with distilled water (until the total volume is 1500 mL).


How many moles of HCL gas are contained in 25 ml of a 0.10 M solution of the acid?

you cant solve that without the concentration of the HCl or the mass if you have either of these use: To find the moles with mass of HCl you have use n= m/mm , m=mass of HCl and mm = the molar mass so the elements mass combined from periodic table to find the moles with the volume = 0.06 (in litres must be!) and concentration use n = cv


How do you make 25 mM borate HCL buffer pH 8.8?

Making 25 mm Borate HCL buffer with a pH of 8.8 will require careful calculation and measurement. The pH can be easily adjusted after formulation. Temperature can impact the pH.


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