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The mass depends on how much you use but the molecular mass would be 160.31gmol as it is Al2Cl3.
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What is the molar mass of aluminum chloride?
The molar mass aluminum chloride is 133,34 g (for the anhydrous salt).
The molar mass of aluminum chloride is?
133 A+
What is the maximum mass of aluminum chloride that can be formed when reacting 15.0 g of aluminum with 20.0 g of chlorine?
The maximum mass of Aluminium chloride formed will be 25.07g.
What is the maximum mass of aluminum chloride that can be formed when reacting 24.0 g of aluminum with 29.0 g of chlorine?
The gram atomic mass of aluminum is 26.9815; the gram atomic mass of chlorine is 35.453; and the formula of aluminum chloride is AlCl3, showing that three atoms of chlorine are required for each atom of aluminum in the compound. Therefore, mass ratio of chlorine to aluminum in the compound is [3 X (35.453])/26.9815 or 3.942. The ratio of reactant chlorine stated to be available to reactant aluminum stated to be available is 29.0/24.0 or 1.20, so that chlorine is clearly the limiting reactant. Therefore, the mass of aluminum in the maximum mass of aluminum chloride that can be made from the reactants stated is 29.0/3.942 or about 7.357 grams, and that added to the stated 29.0 g of chlorine constitutes 36.4 grams total of aluminum chloride, to the justified number of significant digits.
How do you recover aluminum chloride?
what are the steps in recover aluminum chloride?
The molar mass of aluminum chloride is grams?
The molar mass of anhydrous aluminum chloride is 133,34 grams.
What is the molar mass of aluminum chloride?
The molar mass aluminum chloride is 133,34 g (for the anhydrous salt).
The molar mass of aluminum chloride is?
133 A+
What is the maximum mass of aluminum chloride that can be formed when reacting 15.0 g of aluminum with 20.0 g of chlorine?
The maximum mass of Aluminium chloride formed will be 25.07g.
What is the molar mass for aluminum chloride?
133 or 133.3
Why is the term molecular mass applied to water but the term formula mass applied to aluminum chloride?
molecular formula is referred to water because they are covalent compounds while formula mass for aluminum chloride because they are ionic compounds
What is the substance that has formula mass of 133.5 amu?
Aluminum Chloride - Alcl3
What is the maximum mass of aluminum chloride that can be formed when reacting 24.0 of aluminum with 29.0 of chlorine?
36.4 Grams
What is the formula mass of a molecule of aluminum chloride if the mass number of aluminum is 27 and chlorine is 35?
Aluminium's (Al) molar mass is = 27 Chloride (Cl3 ) molar mass is = 106.5 ( since its 35.5 * 3) You add those both up and you get = 133.5
Converting between moles of aluminum chloride and grams of aluminum chloride is most similar to what calculations?
The molecular mass of AlCl3 is 133,340 538 6 g.
What is the maximum mass of aluminum chloride that can be formed when reacting 24.0 g of aluminum with 29.0 g of chlorine?
The gram atomic mass of aluminum is 26.9815; the gram atomic mass of chlorine is 35.453; and the formula of aluminum chloride is AlCl3, showing that three atoms of chlorine are required for each atom of aluminum in the compound. Therefore, mass ratio of chlorine to aluminum in the compound is [3 X (35.453])/26.9815 or 3.942. The ratio of reactant chlorine stated to be available to reactant aluminum stated to be available is 29.0/24.0 or 1.20, so that chlorine is clearly the limiting reactant. Therefore, the mass of aluminum in the maximum mass of aluminum chloride that can be made from the reactants stated is 29.0/3.942 or about 7.357 grams, and that added to the stated 29.0 g of chlorine constitutes 36.4 grams total of aluminum chloride, to the justified number of significant digits.
How many grams of aluminum chloride are produced when 18 grams of aluminum are reacted with an excess of hydrochloride acid?
The empirical formula for aluminum chloride is AlCl3, and its gram formula mass is 133.34. The formula shows that each formula unit contains one aluminum atom, and the the gram atomic mass of aluminum is 26.9815. Therefore, 18(133.34/26.9815) or 89 grams, to the justified number of significant digits, of aluminum chloride will be produced.
