12 carbon monoxides due to lack of enough oxygen when it was being formed
2c6h14 + 15o2 -> 12co2 + 14h2o Stupid site again!! All letters are capitals.
Combustion reactions involve reacting a substance with oxygen to form oxides of the elements that made up the substance. In the case of C3H8 this means carbon dioxide and water: C3H8 + 5 O2 ----> 3 CO2 + 4 H2O
2c6h14 + 15o2 -> 12co2 + 14h2o Stupid site again!! All letters are capitals.
I get 2C6H14+19O2------->12CO2+14H2O
Balanced equation first, 2C6H14 + 19O2 >> 12CO2 + 14H2O 84.4 moles hexane (12 moles CO2/2 moles C6H14) = 506.4 moles of CO2
2c6h14 + 15o2 -> 12co2 + 14h2o Stupid site again!! All letters are capitals.
Yes*. The empirical equation for this reaction is: 2C6H14 + 19O2 ---> 12CO2 + 14H2O. * n-Hexane, burned in an Iron III-catalyzed environment of pure oxygen gas, is oxidized completely. Intermediate products, such as peroxides are formed but the final products are carbon dioxide and water.
Combustion reactions involve reacting a substance with oxygen to form oxides of the elements that made up the substance. In the case of C3H8 this means carbon dioxide and water: C3H8 + 5 O2 ----> 3 CO2 + 4 H2O
Burning is a combustion reaction where the substance being burned reacts with oxygen to form simpler products. For example, the combustion of hexane follows the following balanced reaction: 2C6H14 + 19O2 --> 12CO2 + 14H2O The complete combustion of simple hydrocarbons containing only carbon and hydrogen always produces carbon dioxide and water. Incomplete combustion can also occur, where both carbon monoxide and carbon dioxide are formed in addition to water. Incomplete combustion is more likely to occur in oxygen poorer environments.
Complete combustion is easy. Incomplete combustion is trickier, because there really isn't such a thing as the balanced equation for that, there are several possible balanced equations for that.
The reaction is:C6H12 + 9 O2 = 6 CO2 + 6 H2O
Balanced reaction: C4H10 + 13/2 O2 --> 4CO2 + 5H2O
4C2H5NH2(g)+ 15O2(g) --> 8CO2(g) + 14H2O(l) + 2N2(g)
This can be done precisely under certain conditions, but in practice things aren't so simple. You need to know the exact chemical formula of the thing being burned (this can be difficult if you are burning wood, for instance, which is a complex mixture of thousands of compounds). You also have to assume that the combustion is complete -- in other words that all hydrocarbons are completely converted into carbon dioxide and water, which is not always the case in normal burning situations. The actual reactions that occur while burning something are very complicated in fact, but to a close approximation, you can figure out the amount of CO2 produced in the following way:First, write the balance equation for the combustion of the hydrocarbon. The reactants are the hydrocarbon itself and oxygen gas (O2). The products are carbon dioxide and water. See the Related Questions to the left for how to do this.Then use stoichiometry to figure out for a certain amount of hydrocarbon burned how much CO2 you will produce. See the Related Questions links to the left for how to do this also.See the Related Questions links to the left for detailed instructions on how to do each of these steps! Note that in both of the related questions, example problems have been worked out using the combustion of a hydrocarbon! Most of the work is done for you already! Just see the examples in the linked questions to the left.