The reaction is:
C6H12 + 9 O2 = 6 CO2 + 6 H2O
The balanced decomposition chemical equation for hexane (C6H14) is: 2C6H14 → 6C + 7H2
This depends on how much hexane was being burned and how much oxygen was present.Because the complete combustion of carbon involves placing two moles of oxygen on one mole of carbon plus the formation of water, you would need 19 moles of diatomic oxygen for every one mole of hexane.1 C6H14 + 19 O2 --> 6 CO2 + 7 H2O
Benzene burns with a sooty flame due to its incomplete combustion, which results in the formation of carbon particles (soot). Hexane, on the other hand, is a saturated hydrocarbon and tends to undergo complete combustion, resulting in a cleaner flame with less soot formation.
When hexane (C6H14) reacts with oxygen gas (O2) in the presence of heat or a spark, combustion occurs producing carbon dioxide (CO2) and water (H2O) as the main products. The balanced chemical equation for this reaction is: 2 C6H14 + 19 O2 -> 12 CO2 + 14 H2O.
The balanced equation for complete combustion of heptane is C7H16 + 11O2 ---(ignition)---> 7CO2 + 8H2O. For each moelcule of heptane, you would need 11 molecules of oxygen gas.
The complete combustion of hexane (C₆H₁₄) can be represented by the balanced equation: [ \text{C}6\text{H}{14} + 7\text{O}_2 \rightarrow 6\text{CO}_2 + 7\text{H}_2\text{O} ] In this reaction, for every molecule of hexane combusted, 7 molecules of water (H₂O) are formed.
The balanced decomposition chemical equation for hexane (C6H14) is: 2C6H14 → 6C + 7H2
Yes*. The empirical equation for this reaction is: 2C6H14 + 19O2 ---> 12CO2 + 14H2O. * n-Hexane, burned in an Iron III-catalyzed environment of pure oxygen gas, is oxidized completely. Intermediate products, such as peroxides are formed but the final products are carbon dioxide and water.
Hexane + Oxygen -> Carbon Dioxide + Water - for full combustion Hexane + Oxygen -> Carbon + Carbon Monoxide + Water - for partial combustion
To determine the number of moles of carbon dioxide produced when hexane is burned, we need to consider the balanced chemical equation for the combustion of hexane, which is C6H14 + 19/2 O2 -> 6 CO2 + 7 H2O. From the balanced equation, we can see that for every mole of hexane burned, 6 moles of carbon dioxide are produced. Therefore, if 84.4 moles of hexane is burned, 6 * 84.4 = 506.4 moles of carbon dioxide would be produced.
2c6h14 + 15o2 -> 12co2 + 14h2o Stupid site again!! All letters are capitals.
2c6h14 + 15o2 -> 12co2 + 14h2o Stupid site again!! All letters are capitals.
This depends on how much hexane was being burned and how much oxygen was present.Because the complete combustion of carbon involves placing two moles of oxygen on one mole of carbon plus the formation of water, you would need 19 moles of diatomic oxygen for every one mole of hexane.1 C6H14 + 19 O2 --> 6 CO2 + 7 H2O
The energy released in the combustion of hexane is approximately 46.8 megajoules per gram of hexane combusted.
Benzene burns with a sooty flame due to its incomplete combustion, which results in the formation of carbon particles (soot). Hexane, on the other hand, is a saturated hydrocarbon and tends to undergo complete combustion, resulting in a cleaner flame with less soot formation.
The chemical formula of hexane is C6H14. To find the mass of CO2 produced, first calculate the molar mass of hexane. Then use stoichiometry to find the molar ratio between hexane and CO2. Finally, calculate the mass of CO2 produced using this ratio and the given mass of hexane.
The combustion of hexane (C6H14) produces carbon dioxide (CO2) according to the reaction: C6H14 + 7O2 → 6CO2 + 7H2O. For every 1 gram of hexane burned, approximately 3.03 grams of carbon dioxide are produced. Therefore, from the combustion of B grams of hexane, the amount of carbon dioxide produced would be approximately 3.03B grams.