+1 for H
-2 for O
+6 for S
The correct chemical formula should be P2O5 or P4O10 (its dimer) and not P3O10 (as originally asked in the question). The oxidation numbers are -2 for each O +5 for each P
+2 for Mg +4 for C -2 for each O
In N2O3, the oxidation number of nitrogen (N) is +3 and the oxidation number of oxygen (O) is -2. This is because the overall charge of the compound is zero, and nitrogen typically has a +3 oxidation state in nitrogen oxides.
Yes, the reaction N2O4 -> 2NO2 is a redox reaction because nitrogen changes its oxidation state from +4 to +2, while oxygen changes its oxidation state from -2 to 0. This indicates a transfer of electrons between the reactants.
This answer is -1.To find this answer:Oxygen has an oxidation number of -2.Hydrogen has an oxidation number of +1, and there are 3 of themyou want to get the oxidation numbers to add up to 0, so it would be neutral.-2 + 3(+1) = +1Now, to get this to equal zero, it means that N has to be -1.
It would have been plus seven if possible, however the maximum is the number of valence electron of sulfur to be donated, so that is clearly +6 (six!).In H2S2O7 the oxidation number is +6
Formula: H2S2O7
Sulphuric anhydride is H2S2O7,... H2SO4 + H2SO4-----> H2S2O7 + H2O
A metal typically has only positive oxidation numbers, while a nonmetal can have both positive and negative oxidation numbers. Metals tend to lose electrons (positive oxidation numbers) to form cations, while nonmetals can gain or lose electrons to form a variety of oxidation states.
The density of H2S2O7, also known as disulfuric acid, is approximately 1.90 g/cm^3 at room temperature.
It shows some oxidation numbers. Generally it shows +4 oxidation numbers.
No, the can only have positive oxidation numbers
The sum of the oxidation numbers for P2O5 is zero. In P2O5, the oxidation number for phosphorus is +5, and each oxygen atom has an oxidation number of -2. Since there are five oxygen atoms, the total sum of the oxidation numbers is 2(+5) + 5(-2) = 0.
The oxidation numbers in PO43- , phosphorus oxidation number=+5; oxygen = -2
The simple answer is not always. The stoicheometry deals with oxidation numbers only in redox reactions. The ratio of the change in oxidation numbers is straightly its stoicheometry.
The sum of the oxidation numbers in a neutral compound is equal to zero. This is because in a neutral compound, the total positive oxidation numbers are balanced by the total negative oxidation numbers to give a net charge of zero.
The sum of oxidation numbers in a neutral compound is always zero, as the charges balance out. In polyatomic ions, the sum of oxidation numbers equals the charge of the ion. When determining oxidation numbers, rules such as assigning elements in their elemental state an oxidation number of zero and hydrogen an oxidation number of +1 are typically followed.